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Aleksandr [31]
3 years ago
6

if a caterpillar is moving in a straight line at a speed of 7 cm/s, how long will it take the caterpillar to reach a green, leaf

y plant that is 56 cm away?
Physics
2 answers:
Shkiper50 [21]3 years ago
8 0
At the speed of 8 cm/s
Dmitry [639]3 years ago
8 0

Answer:

8 seconds

Explanation:

Given data

  • Speed of the caterpillar (v): 7 cm/s
  • Distance traveled (d): 56 cm
  • Time elapsed (t): ?

We can find the time that it takes the caterpillar to reach the leafy plant using the following expression.

v = d/t

t = d/v = 56 cm / (7 cm/s) = 8 s

It will take 8 seconds to the caterpillar to reach the leafy plant.

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That ratio is called"efficiency".  It doesn't need to be a percent. 
It can just as well be a fraction or a decimal number.

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A gas is confined to a cylinder under constant atmospheric pressure, as illustrated in the following figure. When the gas underg
GarryVolchara [31]
From the first law of thermodynamics, we use the equation expressed as:

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Hope this answers the question. Have a nice day.
7 0
2 years ago
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Halley's comet orbits the sun roughly once every 76 years. It comes very close to the surface of the Sun on its closest approach
Licemer1 [7]

Answer:

r1 = 5*10^10 m , r2 = 6*10^12 m

v1 = 9*10^4 m/s

From conservation of energy

K1 +U1 = K2 +U2

0.5mv1^2 - GMm/r1 = 0.5mv2^2 - GMm/r2

0.5v1^2 - GM/r1 = 0.5v2^2 - GM/r2

M is mass of sun = 1.98*10^30 kg

G = 6.67*10^-11 N.m^2/kg^2

0.5*(9*10^4)^2 - (6.67*10^-11*1.98*10^30/(5*10^10)) = 0.5v2^2 - (6.67*10^-11*1.98*10^30/(6*10^12))

v2 = 5.35*10^4 m/s

3 0
3 years ago
As you may well know, placing metal objects inside a microwave oven can generate sparks. Two of your friends are arguing over th
poizon [28]

Answer:

4.048\times 10^{-7}\ m

Explanation:

h = Planck's constant = 6.626\times 10^{-34}\ m^2kg/s

c = Speed of light = 3\times 10^8\ m/s

E = Energy = 4.91\times 10^{-19}\ J

Wavelength ejected is given by

\lambda=\dfrac{hc}{E}\\\Rightarrow \lambda=\dfrac{6.626\times 10^{-34}\times 3\times 10^8}{4.91\times 10^{-19}}\\\Rightarrow \lambda=4.048\times 10^{-7}\ m

The maximum wavelength in angstroms of the radiation that will eject electrons from the metal is 4.048\times 10^{-7}\ m

4 0
3 years ago
HELP I NEED THIS ANSWERED AS FAST AS POSSIBLE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
WITCHER [35]

Displacement is d  


Vf² = Vi² + 2 g d  


(-20²) = (+10²) + 2 (-9.8) d  


-19.6 d = 300  


d = -15.3 m  


negative means lower


time is t  


d = Vi t + 1/2 g t²



-15.3 = 10 t + (-4.9) t²



4.9 t² - 10 t -15.3 = 0  


t = 3.06 s

Hope this helps -John

8 0
3 years ago
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