How many protons, neutrons, and electrons do beryllium have?

A ___________________________ is made of two or more different substances.

Dmitry [639]

Mixture/ compound
hope this helps

6 0

3 years ago

1) For the following reaction, 8.44 grams of carbon (graphite) are allowed to react with 9.63 grams of oxygen gas.C(graphite)(s)

Yuki888 [10]

Answer:

The answers to the question are

(a) 13.24 g

(b) (O₂)

(c) 4.8252 g

(2) 0.662 M/L

Explanation:

(a) To solve the question we write the equation as follows

C + O₂ → CO₂

That is one mole of graphite reacts with one mole of oxygen to form one mole of carbon dioxide

number of moles of graphite = 8.44/12 = 0.703 moles

number of moles of oxygen = 9.63/32 = 0.3009

However since one mole of graphite reacts with one mole of oxygen to form one mole of carbon dioxide, therefore, 0.3009 moles of oxygen will react with 0.3009 moles of carbon to fore 0.3009 moles of CO₂

The maximum mass of carbon dioxide that can be formed = mass = moles × molar mass

= 0.3009×44 = 13.24 g

(b) The formula for the limiting reagent (O₂)

Finding the limting reagent is by checking the mole balance of the reactants available to the moles specified in th stoichiometry of the reaction and selecting the reagent with the list number of moles

(c) The mass of excess reagent = 0.703 moles - 0.3009 moles = 0.4021 moles

mass of excess reagent = 0.4021 × 12 = 4.8252 g

(2) The molarity is given by number of moles per liter of solution, therefore

molar mass of mgnesium iodide = 278.1139 g/mol, number of moles of magnesium iodide in 23 g = 23g/ 278.1139 g/mol= 8.3 × 10⁻² M

Therefore the moles in 125 mL = (8.3 × 10⁻² M)/(125 mL) = (8.3 × 10⁻² M)/(0.125 L) = 0.662 M/L

3 0

3 years ago

Write a balanced equation for the reaction of Na₂S and CdSO₄. Express your answer as a chemical equation. Identify all of the ph

Luba_88 [7]

Explanation:

A chemical reaction equation that contains same number of atoms on both reactant and product side is known as a balanced chemical reaction equation.

For example, $Na_{2}S(aq) + CdSO_{4}(aq) \rightarrow Na_{2}SO_{4}(aq) + CdS(s)$

Here, number of reactant molecules are as follows.

Na = 2

S = 2

Cd = 1

O = 4

Number of product molecules are as follows.

Na = 2

S = 2

Cd = 1

O = 4

As there are already equal number of atoms on both reactant and product side. Hence, the reaction equation is balanced.

Also, in this reaction both $Na_{2}S$ and $CdSO_{4}$ are present as aqueous solution. And, CdS is the precipitate that is formed as it is the insoluble solid that forms.