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prohojiy [21]
3 years ago
9

What is the volume of 4.00 moles of CO2 gas at STP?

Chemistry
1 answer:
likoan [24]3 years ago
8 0

Answer:

89.6L

Explanation:

1mole of any gas occupies 22.4L. This simply means that,

1mole of CO2 occupies 22.4L at stp.

Therefore, 4moles of CO2 will occupy = 4 x 22.4 = 89.6L

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Write down five laboratory safety rules.
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Answer:

Five Laboratory Safety Rules:

1). Do not eat in the laboratory.

2). Do not touch any chemical or reagent unless you are told to do so.

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4). Don't remove labels on any reagent.

5). Don't taste anything in the laboratory, no matter how familiar it appears.

Hope it helps.

5 0
3 years ago
Glucose (C6H12O6) can be fermented to yield ethanol (CH3CH2OH) and carbon dioxide (CO2). C6H12O6⟶2CH3CH2OH+2CO2 The molar mass o
jekas [21]

Answer:

The % yield is 74.45 %

Explanation:

<u>Step 1:</u> The balanced equation

C6H12O6⟶2CH3CH2OH+2CO2

<u>Step 2</u>: Data given

Molar mass glucose = 180.15 g/mol

Molar mass of ethanol = 46.08 g/mol

Molar mass of carbon dioxide = 44.01 g/mol

Mass of glucose = 61.5 grams

Mass of ethanol = 23.4 grams

<u>Step 3:</u> Calculate moles of glucose

Moles glucose = Mass glucose  / Molar mass of glucose

Moles glucose = 61.5 grams / 180.15 g/mol

Moles glucose = 0.341 moles

<u>Step 4:</u> Calculate moles of ethanol

1 mole of glucose consumed, produces 2 moles of ethanol and 2 moles of CO2

0.341 moles of glucose, will produce 2*0.341 = 0.682 moles of ethanol

<u>Step 5:</u> Calculate mass of ethanol

Mass ethanol = moles ethanol * Molar mass ethanol

Mass ethanol = 0.682 moles * 46.08 g/mol

Mass ethanol = 31.43 grams = theoretical mass

<u>Step 6:</u> Calculate % yield

% yield = actual mass / theoretical mass

% yield = (23.4 grams / 31.43 grams) * 100%

% yield = 74.45 %

The % yield is 74.45 %

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Because of the sea waters density. If an object is less dense than the water it would not float
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Explanation:

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