Joe throws a ball straight down a 100 m building with a velocity of 5 m/s. How long does it take the ball to reach the ground?

If a certain mass of mercury has a volume of 0.002 m3 at a temperature of 20°C, what will be the volume at 50°C?

Klio2033 [76]

From tables, the density of mercury is
13545 kg/m^3 at 20°C,
13472 kg/m^3 at 50°C.

Because mass = density * volume, the mass of mercury at 20°C is
m = (13545 kg/m^3)*(0.002 m^3) = 27.09 kg

Let V = volume of mercury at 50°C.
Because the mass of mercury does not change, therefore at 50°C,
(13472 kg/m^3)*(V m^3) = 27.09
V = 27.09/13472 = 0.0020108 m^3

Answer: B. 0.002010812 m³

5 0

3 years ago

Suppose that you are headed toward a plateau 4040 m high. If the angle of elevation to the top of the plateau is 2020degrees°,

Lelu [443]

Answer :

The distance is 109.89 m.

Explanation :

Given that,

Height = 40 m

Angle = 20°

We need to calculate the base of the plateau

Using formula of angle

$\tan\thata=\dfrac{h}{x}$

Where, h = height

x = base

$\theta$ = angle

Put the value into the formula

$\tan20^{\circ}=\dfrac{40}{x}$

$x=\dfrac{40}{tan20^{\circ}}$

$x =109.89\ m$

Hence, The distance is 109.89 m.

3 0

3 years ago

How much time does it take Mrs. Spencer to travel 240meters at a speed of 80meters per second?

emmasim [6.3K]

Answer:

3seconds

Explanation:

it will take 3 seconds

7 0

3 years ago

What is transferred by a force moving an object through a distance?

Komok [63]

<span>When you apply force to move an object at a distance, you are applying work. And work is energy in transit. The answer is letter D. For example, you see a cart at a distance. You observe that it is not moving. You want to transfer it to your backyard. You apply force to the cart and observed that the cart is not at the same position as it was before. You are applying work to the cart by transferring your energy to it.</span>

7 0

3 years ago

Read 2 more answers

Under the influence of its drive force, a snowmobile is moving at a constant velocity along a horizontal patch of snow. When the

balandron [24]

Answer:

a) Δx = 11.6 m

b) t = 3.9 s

Explanation:

a)

Since the snowmobile is moving at constant speed, and the drive force is 195 N, this means that thereis another force equal and opposite acting on it, according to Newton's 2nd Law, due to there is no acceleration present in the horizontal direction .
This force is just the force of kinetic friction, and is equal to -195 N (assuming the positive direction as the direction of the movement).
Once the drive force is shut off, the only force acting on the snowmobile remains the friction force.
According Newton's 2nd Law, this force is causing a negative acceleration (actually slowing down the snowmobile) that can be found as follows:

$a = \frac{F_{fr} }{m} = \frac{-195N}{128kg} = -1.5 m/s2 (1)$

Assuming the friction force keeps constant, we can use the following kinematic equation in order to find the distance traveled under this acceleration before coming to an stop, as follows:

$v_{f} ^{2} -v_{o} ^{2} = 2* a* \Delta x (2)$

Taking into account that vf=0, replacing by the given (v₀) and a from (1), we can solve for Δx, as follows:

$\Delta x =- \frac{v_{o}^{2}}{2*a} =- \frac{(5.90m/s)^{2}}{2*(-1.5m/s2)} = 11.6 m (3)$

b)

We can find the time needed to come to an stop, applying the definition of acceleration, as follows:

$v_{f} = v_{o} + a*\Delta t (4)$

Since we have already said that the snowmobile comes to an stop, this means that vf = 0.
Replacing a and v₀ as we did in (3), we can solve for Δt as follows:

$\Delta t = \frac{-v_{o} }{a} = \frac{-5.9m/s}{-1.5m/s2} = 3.9 s (5)$

7 0

3 years ago