Question

1. TNT, (C7H5N3O6) reacts explosively with oxygen gas (O2) to produce CO2 gas, water vapor, and N2 gas. If James weighs out 0.853 g of TNT, answer the following question: How many mg of O2 will react with the TNT?

Answer 1

4C7H5N3O6 + 21O2 = 28CO2 + 10H2O + 6N2

According to the reaction equation, it can be seen that TNT and O2 have following stoichiometric ratio:

n(C7H5N3O6) : n(O2) = 4 : 21

n(O2) = 21/4 x n(C7H5N3O6) = 5.25 x n(C7H5N3O6)


n(C7H5N3O6) = m/M= 0.853/227 = 0.0038 mole


n(O2) = 5.25 x n(C7H5N3O6) = 5.25 x 0.0038 = 0.02 mole


m(O2) = n x M = 0.02 x 32 = 0.64 g = 640mg

Answer 2

Answer:

631.3 milligrams of oxygen gas will react with the TNT.

Explanation:

$4C_7H_5N_3O_6+21O_2\rightarrow 28CO_2+10H_2O+6N_2$

Moles of TNT = $\frac{0.853 g}{227 g/mol}=0.003758 mol$

According to reaction , 4 moles of tNT react with 21 moles of oxygen gas.

Then 0.003758  moles of TNT will react with:

$\frac{21}{4}\times 0.003758 mol=0.01973 mol$

Mass of 0.01973 moles of oxygen ;

$0.01973 mol\times 32 g/mol=0.6313 g=631.3 mg$

( 1 g = 1000 mg)

631.3 milligrams of oxygen gas will react with the TNT.