Answer:
SO3 2- which is sulfite
i have to put this because it doesnt let me send the answer like that :)
Question:
<span>A sample of nitrogen gas had a volume of 500mL, a pressure in its closed container of 740 torr and a temperature of 25°c. what was the volume of gas when the temperature was changed to 50°c and the new pressure was 760 torr?
Answer:
Data Given:
V</span>₁ = 500 mL
P₁ = 740 torr
T₁ = 25 °C + 273 = 298 K
V₂ = ?
P₂ = 760 torr
T₂ = 50 °C + 273 = 323 K
Solution:
Let suppose the gas is acting Ideally, then According to Ideal Gas Equation,
P₁ V₁ / T₁ = P₂ V₂ / T₂
Solving for V₂,
V₂ = (P₁ V₁ T₂) ÷ (T₁ P₂)
Putting Values,
V₂ = (740 torr × 500 mL × 323 K) ÷ (298 K × 760 torr)
V₂ = 527.68 mL
Answer:
The dissociation constant of phenol from given information is
.
Explanation:
The measured pH of the solution = 5.153

Initially c
At eq'm c-x x x
The expression of dissociation constant is given as:
![K_a=\frac{[C_6H_5O^-][H^+]}{[C_6H_5OOH]}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5BC_6H_5O%5E-%5D%5BH%5E%2B%5D%7D%7B%5BC_6H_5OOH%5D%7D)
Concentration of phenoxide ions and hydrogen ions are equal to x.
![pH=-\log[x]](https://tex.z-dn.net/?f=pH%3D-%5Clog%5Bx%5D)
![5.153=-\log[x]](https://tex.z-dn.net/?f=5.153%3D-%5Clog%5Bx%5D)



The dissociation constant of phenol from given information is
.
repartExiplanation:cionde atomos