Which method would be effective for separating salt and water in a mixture?

1 answer:

6 0

A seperation method that would be most successful woth the separation of a salt and water mixture would be evaporation for these reasons, (1) There are no magnetic elements involved with salt nor with water, (2) Observing colour differences would not have much affect on separating the two, and (3) Chromatography is used to separate two liquids, such as speparating two dyes, not salt and water.

Evaporation:
The water will evaporate, leaving you with salt as a solid.

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krek1111 [17]

Answer: 13.9 g of $H_2O$ will be produced from the given mass of oxygen

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of} O_2=\frac{28.8g}{32.00g/mol}=0.900moles$

The balanced chemical reaction is:

$4NIO_2(g)+7O_2(g)\rightarrow 4NO_2(g)+6H_2O(g)$

According to stoichiometry :

7 moles of $O_2$ produce = 6 moles of $H_2O$

Thus 0.900 moles of $O_2$ will produce = $\frac{6}{7}\times 0.900=0.771moles$ of $H_2O$

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Thus 13.9 g of $H_2O$ will be produced from the given mass of oxygen

5 0

2 years ago

What is the volume at stp of 720.0 ml of a gas collected at 20.0 °c and 3.00 atm pressure?

MArishka [77]

Combined gas law is
PV/T = K (constant)

P = Pressure
V = Volume
T = Temperature in Kelvin

For two situations, the combined gas law can be applied as,
P₁V₁ / T₁ = P₂V₂ / T₂

P₁ = 3.00 atm P₂ = standard pressure = 1 atm
V₁ = 720.0 mL T₂ = standard temperature = 273 K
T₁ = (273 + 20) K = 293 K

By substituting,
3.00 atm x 720.0 mL / 293 K = 1 atm x V₂ / 273 K
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quester [9]

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2 years ago

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tatyana61 [14]

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