All categories

3 years ago

What mass, in grams, of oxygen gas (o2) is contained in a 8.5-liter tank at 32.0 degrees celsius and 3.23 atmospheres?

1 answer:

5 0

For this problem we assume that oxygen is an ideal gas. So, we use the equation PV=nRT where P is pressure, V is the volume, n is the number of moles, R is a universal constant and T is the temperature. We first solve for the number of moles n. Then, using the molar mass of oxygen we convert it to grams.

PV=nRT
n = PV / RT
n = 3.23 (8.5) / 0.08206 (32+273.15)
n = 1.0964 mol

mass = 1.0964 mol (32g / 1 mol) = 35.09 g O2

You might be interested in

All of the following pairs of ions are isoelectronic except which one?

mash [69]

Answer: Fe2+ & Mn3+

Explanation:

6 0

3 years ago

A vessel contains a mixture of gases. The mass of each gas used to make the mixture is known. Which of the following information

faltersainse [42]

Answer: The molar mass of each gas

Explanation:

Mole fraction is the ratio of moles of that component to the total moles of solution. Moles of solute is the ratio of given mass to the molar mass.

$\text{Mole fraction of solute}=\frac{\text{Moles of solute}}{\text{Total Moles}}$

Suppose if there are three gases A, B and C.

a) $\text{Mole fraction of A}=\frac{\text{Moles of A}}{\text{ Moles of (A+B+C)}}$

b) $\text{Mole fraction of B}=\frac{\text{Moles of B}}{\text{ Moles of (A+B+C)}}$

c) $\text{Mole fraction of C}=\frac{\text{Moles of C}}{\text{ Moles of (A+B+C)}}$

moles of solute = $\frac{\text {given mass}}{\text {Molar mass}}$

Thus if mass of each gas is known , we must know the molar mass of each gas to know the moles of each gas.

8 0

3 years ago

Can you help me out plz and thank u

Nonamiya [84]

Answer:

stirring

Explanation:

when you stir it spreads the item out more to be fully covered and dissolve faster. like putting sugar in tea, if you don' t stir it wont dissolve fast

5 0

3 years ago

Extend the aufbau sequence through an element that has not yet been identified, but whose atoms would completely fill 7p orbital

Thepotemich [5.8K]

Answer:

Number of electrons = 118

Electronic configuration: [Rn] 5f¹⁴ 6d¹⁰ 7s² 7p⁶

Explanation:

Given: A chemical element that has completely filled 7p orbital.

According to this, the principal occupied electron shell or the valence shell of such an element is 7p.

⇒ the principal quantum number (n) for the valence shell is 7.

∴ this element belongs to the period 7 of the periodic table.

Also, an element that has completely filled p-orbital belongs to the group 18 of the p-block.

Therefore, an element that belongs to the group 7 and period 18 of the periodic table, should have a completely filled 5f, 6d, 7s and 7p orbitals.

Therefore, the electronic configuration should be: [Rn] 5f¹⁴ 6d¹⁰ 7s² 7p⁶

And, the number of electrons = atomic number of radon (Rn) + 14 + 10 + 2 + 6 = 86 + 32 = 118.

Therefore, the given element has atomic number 118 and has the electronic configuration: [Rn] 5f¹⁴ 6d¹⁰ 7s² 7p⁶. Thus the given element can be Oganesson.

7 0

3 years ago

How long will it take a traveling 350m/s to go a distance of 1400m?

lana66690 [7]

Answer:

6 hours

Explanation:

pls brailiest

6 0

2 years ago

Read 2 more answers