Answer:
The correct answer is a
Explanation:
At projectile launch speeds are
X axis vₓ = v₀ = cte
Y axis = v_{oy} –gt
The moment is defined as
p = mv
For the x axis
pₓ = mvₓ = m v₀ₓ
As the speed is constant the moment is constant
For the y axis
p_{y} = m v_{y} = m (v_{oy} –gt) = m v_{oy} - m (gt)
Speed changes over time, so the moment also changes over time
Let's examine the answer
i True
ii False. The moment changes with time
The correct answer is a
"Valence" electrons or the free electrons
<u>Explanation:</u>
Electrical conductivity can be defined as the property of the substance to conduct electricity, heat etc through it. This conductivity is caused due to the migration of particles which are electrically charged within the atomic lattice of the substance.
The outermost electrons or the electrons in valence shell are the main cause behind the conductivity property exhibited by any substance. Higher the number of electrons in outer shell, higher the conductivity.
Since these electrons are in the outermost shell, they can move easily. Under an impact of applied heat, charge these electrons migrate through the atomic lattice and thus conducts electricity, heat as the case may be.
Answer:
Explanation:
It says “Momentum before the collision is equal to momentum after the collision.” Elastic Collision formula is applied to calculate the mass or velocity of the elastic bodies.
Answer:
a) The magnitude of the magnetic field inside the toroid at the inner radius is
0.000447 T = 0.447 mT
b) The magnitude of the magnetic field inside the toroid at the outer radius is
0.000344 T = 0.344 mT
Explanation:
With a logical assumption that magnetic permeability of vacuum would be used,
the magnetic field at a distance r, from the centre of the loop is given as
B = μ₀I (N/2πr)
B = ?
μ₀ = (4π × 10⁻⁷) H/m
I = 0.739 A
N = 590 turns
For the inner radius,
r = 19.5 cm = 0.195 m
a) B = μ₀I (N/2πr)
B = (4π × 10⁻⁷ × 0.739 × 590) ÷ (2π × 0.195)
B = 0.0004471897 T = 0.000447 T = 0.447 mT
b) Magnetic field at the outer radius
r(outer) = r(inner) + length of the square
r(outer) = 19.5 cm + 5.83 cm = 25.33 cm = 0.2533 m
B = μ₀I (N/2πr)
B = (4π × 10⁻⁷ × 0.739 × 590) ÷ (2π × 0.2533)
B = 0.0003442637 T = 0.000344 T = 0.344 mT
Hope this Helps!!!