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nasty-shy [4]
3 years ago
11

NEED HELP ASAP

Physics
1 answer:
raketka [301]3 years ago
7 0

Answer:

50km/h

Explanation:

my teatcher said that

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Two persons A and B are walking with speed 5 km/h and 6 km/h
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Answer:

2

Explanation:

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2 years ago
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The first version of a product, which is built and tested during the third stage of technological design, is called a​
Dimas [21]

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The third stage of parturition is called " after-birth".

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A force of 25 newtons moves a box a distance of 4 meters in 5 seconds.
Simora [160]

By definition, we have that the work done is given by:

W = F * d

Where,

F: force in the direction of displacement

d: displaced distance

Substituting values we have:

W = (25) * (4)\\W = 100 Nm

Then, the power is given by:

P = \frac{W}{t}

Where,

t: time

Substituting values we have:

P = \frac{100}{5}

P = 20\frac{Nm}{s}

Answer:

The work done on the box is 100 Nm, and the power is 20 Nm/s.

5 0
3 years ago
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Dust particles in air have a typical mass of 5.0 x 10-16 kg. They undergo irregular motion due to collisions with air molecules.
Mars2501 [29]

Answer:

Rms speed of the particle will be  38.68\times 10^8m/sec

Explanation:

We have given mass of the air particle m=5\times 10^{-16}kg

Gas constant R = 8.314 J/mol-K

Temperature is given T = 27^{\circ}C=273+27=300K

We have to find the root mean square speed of the particle

Which is given by v_{rms}=\sqrt{\frac{3RT}{m}}=\sqrt{\frac{3\times 8.314\times 300}{5\times 10^{-16}}}=38.68\times 10^8m/sec

So rms speed of the particle will be 38.68\times 10^8m/sec

5 0
3 years ago
A 0.0414 kg ingot of metal is heated to 243◦C
tino4ka555 [31]

Answer:

448 J/kg/°C

Explanation:

m₁ C₁ (T₁ − T) + m₂ C₂ (T₂ − T) = 0

(0.0414 kg) C (243°C − 20.4°C) + (0.411 kg) (4186 J/kg/°C) (18°C − 20.4°C) = 0

(9.22 kg°C) C − 4129 J = 0

C = 448 J/kg/°C

3 0
3 years ago
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