2 years ago

Name four types of friction

Physics

1 answer:

Shtirlitz [24]2 years ago

6 0

Answer:

Static Friction-Friction that acts when the two objects are not moving

Sliding Friction-Two solid surfaces slide across each other

Rolling Friction-An object rolls across each other

Fluid Friction-Friction that occurs as an object moves through a fluid

Explanation:

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An object dropped from rest from the top of a tall building on planet x falls a distance d(t)18 left parenthesis t right parenth

melamori03 [73]

displacement is given by equation

$d = 18t^2$

now at t = 5 s the position is

$d_1 = 18 *5^2 = 450 m$

similarly position at t = 9 s

$d_2 = 18*9^2 = 1458 m$

so the displacement of object in given interval of time will be

$d = 1458 - 450 = 1008 m$

time interval

$\delta t = 9 - 5 = 4 s$

now the average velocity will be given as

$v = \frac{\delta x}{\delta t}$

$v = \frac{1008}{4} = 252 m/s$

so its average speed is 252 m/s

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2 years ago

Suppose that the Mars orbiter was to have established orbit at 155 km and that one group of engineers specified this distance as

MAXImum [283]

Answer:

108 km

Explanation:

The conversion factor between meters and feet is

1 m = 3.28 ft

So the second altitude, written in feet, can be rewritten in meters as

$h_2 = 1.55 \cdot 10^5 ft \cdot \frac{1}{3.28 ft/m}=4.7\cdot 10^4 m$

or in kilometers,

$h_2 = 47 km$

the first altitude in kilometers is

$h_1 = 155 km$

so the difference between the two altitudes is

$\Delta h = 155 km - 47 km = 108 km$

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3 years ago

While studying bacterial cells, scientists measure the lengths of the cells in one colony. The chart shows their data.

Hitman42 [59]

The scientists should best deal with this measurement by stating that there was an error during measuring and collect further data.

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2 years ago

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An object is dropped from the top of a tall building. At 2 seconds, it is 64 feet from the top of the building. At 4 seconds, it

jeka94

Answer:

96.21 ft/s

Explanation:

To solve this, you only need to use one expression which is:

Vf² = Vo² + 2gh

g = 9.8 m/s²

However, this exercise is talking in feet, so convert the gravity to feet first:

g = 9.8 * 3.28 = 32.15 ft/s²

Vo is zero, because it's a free fall and in free fall the innitial speed is always zero. With this, let's calculate the speed at 2 seconds, with a height of 64 ft, and then with the 256 ft:

V1 = √2*32.15*64

V1 = 64.15 ft/s

V2 = √2*32.15*256

V2 = 128.3 ft/s

So the average rate is:

V = 128.3 + 64.15 / 2

V = 96.22 ft/s

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2 years ago

A rowboat that is traveling 2.5m/s to the north, encounters a current traveling 4.3m/s to the east. What is the resultant veloci

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