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tekilochka [14]
2 years ago
12

Name four types of friction

Physics
1 answer:
Shtirlitz [24]2 years ago
6 0

Answer:

Static Friction-Friction that acts when the two objects are not moving

Sliding Friction-Two solid surfaces slide across each other

Rolling Friction-An object rolls across each other

Fluid Friction-Friction that occurs as an object moves through a fluid

Explanation:

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A car of mass 500 kg is moving at a speed of 1.2 m/s. A man pushes the car,
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3 years ago
child slides down a snow‑covered slope on a sled. At the top of the slope, her mother gives her a push to start her off with a s
Strike441 [17]

Answer:

θ = 13.7º

Explanation:

  • According to the work-energy theorem, the change in the kinetic energy of the combined mass of the child and the sled, is equal to the total work done on the object by external forces.
  • The external forces capable to do work on the combination of child +sled, are the friction force (opposing to the displacement), and the component of the weight parallel to the slide.
  • As this last work is just equal to the change in the gravitational potential energy (with opposite sign) , we can write the following equation:

       \Delta K + \Delta U = W_{nc} (1)

  • ΔK, is the change in kinetic energy, as follows:

       \Delta K = \frac{1}{2}* m* (v_{f} ^{2}  - v_{0} ^{2}) (2)

  • ΔU, is the change in the gravitational potential energy.
  • If we choose as our zero reference level, the bottom of the slope, the change in gravitational potential energy will be as follows:

        \Delta U = 0 - m*g*h = -m*g*d* sin\theta (3)

  • Finally, the work done for non-conservative forces, is the work done by the friction force, along the slope, as follows:

        W_{nc} = F_{f} * d * cos 180\º \\\\  = 0.2*m*g*d* cos 180\º = -0.2*m*g*d (4)

  • Replacing (2), (3), and (4) in (1), simplifying common terms, and rearranging, we have:

      \frac{1}{2}* (v_{f} ^{2}  - v_{0} ^{2}) = g*d* sin\theta -0.2*g*d

  • Replacing by the givens and the knowns, we can solve for sin θ, as follows:              \frac{1}{2}*( (4.30 m/s) ^{2}  - (0.75 m/s)^{2}) = 9.8 m/s2*25.5m* sin\theta -0.2*9.8m/s2*25.5m\\ \\ 8.56 (m/s)2 = 250(m/s)2* sin \theta -50 (m/s)2\\ \\ sin \theta = \frac{58.6 (m/s)2}{250 (m/s)2}  = 0.236⇒ θ = sin⁻¹ (0.236) = 13.7º
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3 years ago
If a ball has a velocity of 5 m/s and a kinetic energy of 1000 J, what is its mass? ​
zheka24 [161]

Answer: I don't know how to do this

Explanation: sorry I am not sure.

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2 years ago
what is the designation given to a galaxy with a small nuclear bulge and loosely wound arms starting from a a bar through the nu
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In SBc galaxies, both the arms and the bar are highly resolved into star clouds and stellar associations. The arms are open in form and can start either at the ends of the bar or tangent to a ring.

<h3>Is the Milky Way a SBc galaxy?</h3>

Originally thought to be a hubble type Sb or Sc (Sbc), astronomers now believe that the Milky Way is has a central bar and is therefore a loosely wound, barred spiral galaxy – Hubble type SBbc.

<h3>What is the difference between an SBc galaxy and an Sc galaxy?</h3>

Sa (and SBa) galaxy types have tightly wound arms and large central bulges.

Sc's (and SBc's) have loosely wound arms and a small central bulge.

Learn more about SBc galaxy here:

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1 year ago
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