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jenyasd209 [6]
2 years ago
9

When hydrogen combines with oxygen to produce water, this is what kind of reaction?

Chemistry
1 answer:
qwelly [4]2 years ago
7 0

Answer:

The answer to your question is the letter C) Synthesis.

Explanation:

Data

H₂  and O₂ produces water

Balanced chemical reaction

                                2H₂  +  O₂   ⇒   2H₂O

Definition of the kinds of reactions

A) double-displacement   is a reaction where the cations and anions of the reactants are interchanged.

B) endothermic  is the chemical reaction that needs a supply of energy to proceed.

C) synthesis  is the chemical reaction where two reactants combine to form only a product.

D) combustion is the chemical reaction where a compound with carbon reacts with oxygen to form carbon dioxide and water.

Conclusion

From the information given we conclude that the reaction between hydrogen and oxygen is a synthesis reaction.

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Which of the following is a salt that will form from the combination of a strong base with a weak acid?
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Answer:

A. NaHCO₃

Explanation:

NaHCO₃ ⇒ NaOH + H₂CO₃

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A ____________ is a large body that moves around a star?
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A solution of methanol and water has a mole fraction of water of 0.312 and a total vapor pressure of 21 torr at 39.9 degrees C.
Elan Coil [88]

Answer:

Explanation:

Given the details, we can say that

Pure methanol is a volatile solvent as the vapour pressure has a high value. This means that methanol - methanol intermolecular forces are weak in comparisson to water - water forces. When having about 30% of water in a methanol mixture, the mixture Pv decreased, showing that it is not a volatile mixture, so then there are strong intermolecular interactions between methanol - water, part of it due to the hydrogen bonds.

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If the concentration of the stock (provided) Cu(NH3)42 was 0.041 M, what concentration will the Cu2 be in beaker?
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Answer:

[Cu^{2+}]=0.041 M

Explanation:

Hello!

In this case, since the molarity of a solution is defined in terms of the moles of the solute and the volume of solution, given that the concentration of Cu(NH₃)₄²⁺ is 0.041 M, and there is only one copper atom per Cu(NH₃)₄²⁺ ion, we can compute the concentration of Cu²⁺ as shown below:

[Cu^{2+}]=0.041\frac{molCu(NH_3)_4^{2+}}{L}*\frac{1molCu^{2+}}{1molCu(NH_3)_4^{2+}} =0.041 \frac{molCu(NH_3)_4^{2+}}{L}

[Cu^{2+}]=0.041 M

Best regards!

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2 years ago
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