Suppose Sammy Sosa hits a home run which travels 361. ft (110. m). Leaving the bat at 50 degrees above the horizontal, how high
did it travel?
1 answer:
Answer:
The horizontal distance of Sosa is 276.526 ft or 84.28 meter.
Explanation:
As shown in the figure, let point O is the starting point of Sosa. She travels 361 ft at an angle 50 degree with the horizontal.
sin 50 =
0.7660 = h / 361
h = 276.526 ft
h = 84.28 meter
The horizontal distance of Sosa is 276.526 ft or 84.28 meter.
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Answer:
0.5 kg
Explanation:
» <u>Concepts</u>
Newton's second law, the Law of Acceleration, states that F = ma, where F = Force in Newtons, m = mass in kg, and a = acceleration in m/s^2.
» <u>Application</u>
We are asked to find the mass of the ball using the equation F = ma. We're also given the force and acceleration, so the equation looks like 5 = 10(m).
» <u>Solution</u>
Step 1: Divide both sides by 10.
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