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lisov135 [29]
3 years ago
11

Suppose Sammy Sosa hits a home run which travels 361. ft (110. m). Leaving the bat at 50 degrees above the horizontal, how high

did it travel?

Physics
1 answer:
Mashcka [7]3 years ago
5 0

Answer:

The horizontal distance of Sosa is 276.526 ft or 84.28 meter.

Explanation:

As shown in the figure, let point O is the starting point of Sosa. She travels 361 ft at an angle 50 degree with the horizontal.

sin 50 = \frac{OM}{OP}

0.7660 = h / 361

h = 276.526 ft

h = 84.28 meter

The horizontal distance of Sosa is 276.526 ft or 84.28 meter.

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Can someone tell me how this circuit works?
ch4aika [34]

Answer:

In the scientific model, electric current is the overall movement of charged particles in one direction. The cause of this movement is an energy source like a battery, which pushes the charged particles. The charged particles can move only when there is a complete conducting pathway (called a ‘circuit’ or ‘loop’) from one terminal of the battery to the other.

A simple electric circuit can consist of a battery (or other energy source), a light bulb (or other device that uses energy), and conducting wires that connect the two terminals of the battery to the two ends of the light bulb. In the scientific model for this kind of simple circuit, the moving charged particles, which are already present in the wires and in the light bulb filament, are electrons.

Electrons are negatively charged. The battery pushes the electrons in the circuit away from its negative terminal and pulls them towards the positive terminal (see the focus idea Electrostatics – a non contact force). Any individual electron only moves a short distance. (These ideas are further elaborated in the focus idea Making sense of voltage). While the actual direction of the electron movement is from the negative to the positive terminals of the battery, for historical reasons it is usual to describe the direction of the current as being from the positive to the negative terminal (the so-called ‘conventional current’).

The energy of a battery is stored as chemical energy (see the focus idea Energy transformations). When it is connected to a complete circuit, electrons move and energy is transferred from the battery to the components of the circuit. Most energy is transferred to the light globe (or other energy user) where it is transformed to heat and light or some other form of energy (such as sound in iPods). A very small amount is transformed into heat in the connecting wires.

The voltage of a battery tells us how much energy it provides to the circuit components. It also tells us something about how hard a battery pushes the electrons in a circuit: the greater the voltage, the greater is the push (see the focus idea Using energy).

Explanation:

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2 years ago
Velocity must be measured in units of
ohaa [14]
Metres per seconds (m/s)
3 0
3 years ago
A 140 kg load is attached to a crane, which moves the load vertically. Calculate the tension in the cable for the following case
Murljashka [212]

Answer:

The answer is below

Explanation:

A 140 kg load is attached to a crane, which moves the load vertically. Calculate the tension in the

cable for the following cases:

a. The load moves downward at a constant velocity

b. The load accelerates downward at a rate 0.4 m/s??

C. The load accelerates upward at a rate 0.4 m/s??

Solution:

Acceleration due to gravity (g) = 10 m/s²

a) Given that the mass of the crane (m) is 140 kg. If the load moves downward, the tension (T) is given by:

mg - T = ma

Since the load has a constant velocity, hence acceleration (a) = 0. Therefore:

mg - T = m(0)

mg - T = 0

T = mg

T = 140(10) = 1400 N

T = 1400 N

b)  If the load moves downward, the tension (T) is given by:

mg - T = ma

T = mg - ma = m(g - a)

T = 140(10 - 0.4) = 140(9.96) = 134.4

T = 134.4 N

c)  If the load moves upward, the tension (T) is given by:

T - mg = ma

T = ma + mg = m(a + g)

T = 140(0.4 + 10) = 140(10.4)

T = 145.6 N

2) To find the distance (s) if the load move from rest (u= 0) and accelerates for 20 seconds (t = 20). We use:

s = ut + (1/2)gt²

s = 0(20) + (1/2)(10)(20)²

s = 2000 m

7 0
3 years ago
If diameter and length of a cylinder are 0.01 m and 0.07 m respectively, the thermal conductivity of air is 0.028 W/mK and the N
kap26 [50]

Answer:

The convective heat transfer coefficient of the fluid is 170.4 watts per square meter-degree Celsius.

Explanation:

The Nusselt number (Nu) is a dimensionless factor which compares the sensitivity of a fluid due to convection with those due to conduction:

Nu = \frac{h\cdot L_{c}}{k} (Eq. 1)

Where:

h - Convective heat transfer coefficient, measured in watts per square meter-degree Celsius.

k - Conductive heat transfer coefficient, measured in watts per meter-degree Celsius.

L_{c} - Characteristic length, measured in meters.

In addition, the characteristic length of a cylinder is defined by the following formula:

L_{c} = \frac{\pi\cdot r^{3}\cdot l}{2\pi\cdot r^{2}+2\pi\cdot r \cdot l} (Eq. 2)

Where:

r - Radius of the cylinder, measured in meters.

l - Length of the cylinder, measured in meters.

If we know that Nu = 14.2, k = 0.028\,\frac{W}{m\cdot ^{\circ}C}, r = 0.005\,m and l = 0.07\,m, then the convective heat coefficient is:

From (Eq. 2):

L_{c} = \frac{\pi\cdot (0.005\,m)^{2}\cdot (0.07\,m)}{2\pi\cdot (0.005\,m)^{2}+2\pi\cdot (0.005\,m)\cdot (0.07\,m)}

L_{c} = \frac{7}{3000}\,m

And by (Eq. 1):

h = \frac{k\cdot Nu}{L_{c}}

h = \frac{\left(0.028\,\frac{W}{m\cdot ^{\circ}C} \right)\cdot (14.2)}{\frac{7}{3000}\,m }

h = 170.4\,\frac{W}{m^{2}\cdot ^{\circ}C}

The convective heat transfer coefficient of the fluid is 170.4 watts per square meter-degree Celsius.

7 0
2 years ago
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