Suppose Sammy Sosa hits a home run which travels 361. ft (110. m). Leaving the bat at 50 degrees above the horizontal, how high
did it travel?
1 answer:
Answer:
The horizontal distance of Sosa is 276.526 ft or 84.28 meter.
Explanation:
As shown in the figure, let point O is the starting point of Sosa. She travels 361 ft at an angle 50 degree with the horizontal.
sin 50 =
0.7660 = h / 361
h = 276.526 ft
h = 84.28 meter
The horizontal distance of Sosa is 276.526 ft or 84.28 meter.
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Answer:
C. Quadruple the intensity
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Thus, to make a given sound seem twice as loud, the musician should Quadruple the intensity
Answer:
g = 0.85 m
Explanation:
g =
were; g is the acceleration due to Earth's gravity, G is Newton's gravitation constant (6.674 x N
), M is the mass of the earth (5.972 x
kg), and h is the distance of meteoroid to the earth.
h = 3.40 x R
= 3.40 x 6371 km
h = 21661.4 km
= 21661400 m
Thus,
g =
=
= 0.84944
g = 0.85 m
The acceleration due to the Earth's gravitation is 0.85 m.