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satela [25.4K]
3 years ago
9

Karen has a mass of 57.9 kg as she rides the up escalator at Woodley Park Station of the Washington D.C. Metro. Karen rode a dis

tance of 69.6 m, the longest escalator in the free world. The acceleration of gravity is 9.8 m/s 2 . How much work did the escalator do on Karen if it has an inclination of 34.8 ◦ ? Answer in units of J.
Physics
2 answers:
liq [111]3 years ago
8 0

Answer:22537.92 J

Explanation:

Given

mass of karen \left ( m\right )=57.9 kg

Distance covered by Karen =69.6 m

acceleration due to gravity=9.8

inclination=34.8^{\circ}

vertically karen move

h=69.6\times \sin \left ( 34.8\right )

h=39.72 m

Work done by escalator on karen is equal to change in potential energy of  karen

\Delta P.E.=m\times g\times \Delta h

\Delta P.E.=57.9\times 9.8\times 39.72=22537.92 J

Oxana [17]3 years ago
4 0

Answer:

22537.92 J

Explanation:

We are given that

Mass of Karen=57.9 Kg

Karen rode  a distance=69.6 m

Acceleration due to gravity=9.8 m/s^2

\theta=34.8^{\circ}

We have to find the amount of work done by escalator on Karen.

Vertical height of longest escalator=69.6 sin 34.8^{\circ}=39.72 m

Work done=Potential energy of escalator

Work done=mgh=57.9\times 9.8\times 39.72=22537.92 J

Hence, the work done on Karen=22537.92 J

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-- an object is speeding up
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Any one of these changes is acceleration.

There's a single term that covers them all.  It is "change in velocity".


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You know your mass is 62 kg but when you stand on a bathroom scale in an elevator it says your mass is 77 kg what is the acceler
lbvjy [14]
In a stationary situation, the weight of person is
W=mg=(62 kg)(9.81 m/s^2) = 608.2 N
This is the weight "felt" by the scale, which is basically the normal reaction applied by the scale on the person, and which uses the value of g (9.81) as reference to convert the weight (602.8 N) into a mass (62 kg).

When the person is in the elevator, the scale says 77 kg. The scale is still using the same value of conversion (9.81), so the apparent weight "felt" by the scale is
W' = m'g=(77 kg)(9.81 m/s^2)=755.4 N
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\sum F = ma
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a= \frac{W-W'}{m}= \frac{608.2N-755.4N}{62 kg}=-2.37 m/s^2
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4 0
3 years ago
A water bath in a physical chemistry lab is 1.55 m long, 0.710 m wide, and 0.570 m deep (high). If it is filled to within 3.55 i
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Answer:

528 liter.

Explanation:

Volume of the tank(cuboid) = l*b*h

But volume of the water = l*b*h

Where

l= length of the tank

b = width of the tank

h = the length from the bottom of the tank,

3.55 in to m,

0.09017m

Length of the water in the tank = 0.570 - 0.09017

= 0.47983 m.

Volume = 0.47983*0.710*1.55

= 0.528 m3.

1 m3 = 1000 liter.

0.528 m3 = 0.528*1000

= 528 liter

7 0
3 years ago
A 1200 kg sports car accelerates from 0 m/s to 30 m/s in 10 s. What is the average power of the engine?
DIA [1.3K]

Answer:

3600N

Explanation:

Given: m = 1200kg, Vo = 0m/s, Vf = 30m/s, Δt = 10s

ΣF = ma

we need to find 'a' first, using the definition of 'a' we get equation:

a = (Vf-Vo)/Δt

a = (30m/s)/10s

a = 3 m/s^2

now substitute into top equation

ΣF = ma

Fengine = (1200kg)(3m/s^2)

Fengine = 3600N

5 0
2 years ago
Read 2 more answers
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