The answer is 80 atomic mass
Answer:
my answer is b oti d I am not sure
Data:
Molar Mass of NaOH = 40 g/mol
Solving: <span>According to the Law Avogradro, we have in 1 mole of a substance, 6.02x10²³ atoms/mol or molecules
</span>
1 mol -------------------- 6.02*10²³ molecules
y mol -------------------- 2.70*10²² molecules
6.02*10²³y = 0.270*10²³
![y = \frac{0.270*\diagup\!\!\!\!\!\!10^{\diagup\!\!\!\!\!\!23}}{6.02*\diagup\!\!\!\!\!\!10^{\diagup\!\!\!\!\!\!23}}](https://tex.z-dn.net/?f=y%20%3D%20%20%5Cfrac%7B0.270%2A%5Cdiagup%5C%21%5C%21%5C%21%5C%21%5C%21%5C%2110%5E%7B%5Cdiagup%5C%21%5C%21%5C%21%5C%21%5C%21%5C%2123%7D%7D%7B6.02%2A%5Cdiagup%5C%21%5C%21%5C%21%5C%21%5C%21%5C%2110%5E%7B%5Cdiagup%5C%21%5C%21%5C%21%5C%21%5C%21%5C%2123%7D%7D%20%20)
![\boxed{y \approx 0.04\:mol}](https://tex.z-dn.net/?f=%5Cboxed%7By%20%5Capprox%200.04%5C%3Amol%7D)
Solving: <span>Find the mass value now
</span>
40 g ----------------- 1 mol of NaOH
x g ------------- 0.04 mol of NaOH
![x = 40*0.04](https://tex.z-dn.net/?f=x%20%3D%2040%2A0.04)
![\boxed{\boxed{x = 1.6\:g}}\end{array}}\qquad\quad\checkmark](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cboxed%7Bx%20%3D%201.6%5C%3Ag%7D%7D%5Cend%7Barray%7D%7D%5Cqquad%5Cquad%5Ccheckmark)
Answer:
The mass is 1.6 grams
<span>The "exosphere" is the most distant and tenuous "layer" of our atmosphere.</span>