Answer:
Option A and E
Physical properties are not reversible
Answer:
False
Explanation:
The charge on an electron as well as proton is same. The difference between electron and proton is that the electrons have a negative charge while the protons have positive charge.
The weight of an electron is, while the weight of a proton is .
Therefore, the given statement "A proton carries positive charge, and weights the same as an electron." is false.
Answer:
Temperature=3.86*10^7K
V1=1.4
Explanation:
Deuterium (2H), when heated to sufficiently high tempera- ture, undergoes a nuclear fusion reaction that results in the production of helium. The reaction proceeds rapidly at a temperature, T, at which the average kinetic energy of the deuterium atoms is 8 × 10216 J. (At this temperature, deu- terium molecules dissociate completely into deuterium atoms.)
(a) Calculate T in kelvins (atomic mass of 2H 5 2.015).
(b) For the fusion reaction to occur with ordinary H atoms, the average energy of the atoms must be about 32 × 10216 J. By what factor does the average speed of the 1H atoms differ from that of the 2H atoms of part (a)?
k.E =3/2kT
K.E is the kinetic energy
k=boltzmann constant
T=Temperature in kelvin
juxtaposing the given values we have
T=2(KE)/3k
T=2*8*10^-16/(3*1.38*10^-23)
T=3.86*10^7K
Temperature=3.86*10^7K
b. average speed V=
R is the gas constant
T absolute temperature in kelvin
M molar mass
since R.T,PI are constant
we are comparing between hydrogen and helium particles
V=
V1/V2=
V1=V2
V1=V2* 1.4
V1=1.4
ANSWER
Lift frame :
Initial speed of the coin u=0 m/s
Acceleration a=9.8 m/s
2
Initial height of coin from the floor of elevator h=2.45 m
Time taken by coin to hit the floor T=
g
2H
⟹ T=
9.8
2×2.45
=
2
1
s
Hello!
Recall the equation for momentum:
p = linear momentum (kgm/s)
m = mass (kg)
v = velocity (m/s)
<u>Part 1: </u>
We can solve for the total momentum using the above equation. Let m1 represent the 0.2 kg cart, and m2 represent the 0.4 kg cart.
Since they move off together:
<u>Part 2: </u>
Using the conservation of momentum:
m2 was initially at rest, so:
<u>Part 3:
</u>
We can calculate the force by first calculating the impulse exerted on the carts.
Recall the equation for impulse:
We can use either cart, but for ease, we can use the 0.4 cart that starts from rest.
Thus:
Now, calculate force with the following:
Plug in the values: