Answer:
The center of a storm system (Low) over part of the United States and the frontal boundaries associated with this system are shown. Point A represents a location on the map.
Explanation:
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<h3>
Answer:</h3>
1.02 moles
<h3>
Explanation:</h3>
<u>We are given;</u>
N₂O₅ + H₂O → 2HNO₃
- Moles of N₂O₅ is 0.51 moles
We are required to determine the number of moles of HNO₃ produced.
First, we need to identify the mole ratio of N₂O₅ to HNO₃
- From the equation 1 mole of N₂O₅ reacts to produce 2 moles of HNO₃
- Therefore, the mole ratio of N₂O₅ to HNO₃ is 1 : 2
Second; we can determine the moles of HNO₃
Moles of HNO₃ = Moles of N₂O₅ × 2
= 0.51 Moles × 2
= 1.02 moles
Thus, the number of moles of HNO₃ that will be produced is 1.02 moles
Answer:
Mg²⁵ = 10.00%
Mg²⁶ = 45.04%
Mg²⁴ = 44.96%
Explanation:
Given data:
Atomic mass of Mg²⁶ = 25.983
Atomic mass of Mg²⁵ = 24.986
Atomic mass of Mg²⁴ = 23.985
Abundance of Mg²⁵ = 10.00%
Abundance of Mg²⁶ = ?
Abundance of Mg²⁴ = ?
Solution:
Average atomic weight of Mg = 25.983 + 24.986+ 23.985 / 3
Average atomic weight of Mg = 74.954/3
Average atomic weight of Mg = 24.985 amu
Abundance of
Mg²⁵ = 10.00
Mg²⁶ = x
Mg²⁴ = 100- 10 - x = 90 -x
Formula:
Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) + (abundance of 3rd isotope × its atomic mass) / 100
24.985 = (0.1×24.986)+(90-x×23.985) + ( x ×25.983 ) /100
24.985 = 249.86 + 2158.65 - 23.985x + 25.983x / 100
24.985 = 2408.51 + 1.998 x / 100
2498.5 = 2408.51 + 1.998 x
1.998 x = 2498.5 - 2408.51
1.998 x = 89.99
x = 89.99 /1.998
x = 45.04
Now we put the value of x:
Mg²⁵ = 10.00
Mg²⁶ = x (45.04)
Mg²⁴ = 90 -x (90 - 45.04 = 44.96)
Answer:
evaporation?
Explanation:
evaporate the water leaving behind the sand?