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zysi [14]
3 years ago
7

A swan on a lake gets airborne by flapping its wings and running on top of the water. If the swan must reach a velocity of 6.00

m/s to take off and it accelerates from rest at an average rate of 0.350 m/s2, How long does this take (in seconds)
Physics
1 answer:
ira [324]3 years ago
5 0

Answer:

A. 51.42 m.

B. 17.14 s.

Explanation:

Using equations of motion:

vf^2 = vi^2 + 2 * aS

Where,

vf = final velocity

a = acceleration

S = distance to which swan traveled

vi = 0 m/s

6.00^2 = 2 * 0.350S

S = 36/0.7

= 51.42 m.

B.

vf = vi + at

6 = 0 + 0.35t

t = 6/0.35

= 17.14 s.

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Law Incorporation [45]

Answer:

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3 years ago
Two rigid rods are oriented parallel to each other and to the ground. The rods carry the same current in the same direction. The
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Answer:

I = 215.76 A  

Explanation:

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I = 215.76 A  

note:

mathematical calculation maybe wrong or having little bit error but the method is perfectly fine

5 0
3 years ago
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