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Marina CMI [18]
4 years ago
15

What do you call the type of rock from which a soil forms? A. lichen B. clay C. sand D. parent material

Physics
1 answer:
Dmitrij [34]4 years ago
3 0
D
The parent material refers the the rock that was responsible for the formation of a certain soil.
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A certain cable of an elevator is designed to exert a force of 4.5x 104 N. If the maximum acceleration that a loaded car can wit
meriva

Answer: 3,383.5 kg

Explanation:

from the question we were given the following

tension (T) =  4.5 x 10^4 N

maximum acceleration (a) = 3.5 m/s^2

acceleration due to gravity (g) = 9.8 m/s^2  ( it's a constant value )

mass of the car and its contents (m) = ?

we can get the mass of the car and it's contents from the formula for tension which is T = ma + mg

    T = m (a + g)

therefore m = T / (a+g)

m = (4.5 x 10^4 / ( 3.5 + 9.8 )

m = 3,383.5 kg

5 0
3 years ago
PLEASE HELP!
lana66690 [7]

Answer:

x = 4.32 [m]

Explanation:

We must divide this problem into three parts, in the first part we must use Newton's second law which tells us that the force is equal to the product of mass by acceleration.

∑F = m*a

where:

F = force = 700 [N]

m = mass = 2030 [kg]

a = acceleration [m/s²]

Now replacing:

F=m*a\\700=2030*a\\a = 0.344[m/s^{2}]

Then we can determine the final speed using the principle of conservation of momentum and amount of movement.

(m_{1}*v_{1})+Imp_{1-2}=(m_{1}*v_{2})

where:

m₁ = mass of the car = 2030 [kg]

v₁ = velocity at the initial moment = 0 (the car starts from rest)

Imp₁₋₂ = The impulse or momentum (force by the time)

v₂ = final velocity after the impulse [m/s]

(2030*0) + (700*5)=(2030*v_{2})\\3500 = 2030*v_{2}\\v_{2}=1.72[m/s]

Now using the following equation of kinematics, we can determine the distance traveled.

v_{2}^{2} =v_{1}^{2}+2*a*x

where:

v₂ = final velocity = 1.72 [m/s]

v₁ = initial velocity = 0

a = acceleration = 0.344 [m/s²]

x = distance [m]

1.72^{2}=0^{2} +(2*0.344*x) \\2.97 = 0.688*x\\x = 4.32 [m]

8 0
3 years ago
The length of the assembly decreases by 0.006 in. when an axial a- force is applied by means of rigid end plates. Determine
Triss [41]

Answer:

(a) The magnitude of the applied force is (0.0001524k) Newton

(b) Corresponding stress in the steel core = (0.0001524k/area) Newton per meter square

Explanation:

(a) From Hookes law of elasticity,

Force applied = force constant (k) × compression

compression = 0.006 in = 0.006 × 0.0254 = 0.0001524 meter

Force applied = k × 0.0001524 = (0.0001524k) Newton

(b) Stress = Force applied (Newton)/area of steel core (meter square) = (0.0001524k/area) Newton per meter square

6 0
3 years ago
A cell phone weighing 80 grams is flying through the air at 15 m/s what is the kinetic energy
hjlf

Answer:

9\:\mathrm{J}

Explanation:

Kinetic energy is given by the following equation:

KE=\frac{1}{2}mv^2, where m is mass in \mathrm{kg} and v is velocity in \mathrm{m/s}.

Since the cell phone's mass is given in grams, we need to convert this into kilograms:

80\:\mathrm{g}\cdot \frac{1\:\mathrm{kg}}{1000\:\mathrm{g}}=0.08\:\mathrm{kg}.

Therefore, the kinetic energy of the cell phone is:

KE=\frac{1}{2}\cdot 0.08\cdot 15^2=\fbox{$9\:\mathrm{J}$}.

3 0
3 years ago
An automobile engine takes in 4000 j of heat and performs 1100 j of mechanical work in each cycle. (a) calculate the engine's ef
Semmy [17]
(a) The efficiency of an engine is defined as the ratio between the work done by the engine and the heat it takes in:
\eta= \frac{W}{Q_{in}}
The engine in this problem does a work of W=1100 J and it takes in Q_{in}=4000 J of heat, therefore its efficiency is
\eta= \frac{1100 J}{4000 J}=0.275 = 27.5 \%

(b) The heat taken by the machine is 4000 J; of this amount of heat, only 1100 J are converted into useful work. This means that the rest of the heat is wasted. Therefore, the wasted heat is the difference between the heat in input and the work done by the engine:
Q_{wasted}=Q_{in}-W=4000 J-1100 J=2900 J
7 0
3 years ago
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