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Nostrana [21]
3 years ago
6

What is a compound called that has the ability to soak up large amounts of water?

Chemistry
1 answer:
STALIN [3.7K]3 years ago
5 0

Answer:

Hygroscopic substances

Explanation:

Hygroscopic compounds are those that absorb moisture and a large amount of water and they become wet. They should not be confused with deliquescent substances that absorb water and forms solution.

Hygroscopic substances froms pasty substances and not solution while the liquid ones only becomes diluted. Examples are sodium trioxonitrate(v) (NaNO₃), copper (ii) oxide CuO, and concentrated tetraoxosulphate (vi) acid (H₂SO₄)

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What is 30-9x2*2-21-4+4
IgorC [24]
Answer:
9 (1-2x²)

Explanation:
The given expression is:
30 - 9x²*2 - 21 - 4 + 4
The first step is to compute the multiplication. This will give:
30 - 18x² - 21 - 4 + 4
Then, we will add like terms as follows:
(30-21-4+4) - 18x²
= 9 - 18x²
Finally, we can take the 9 as a common factor from both terms, this will give:
9 (1-2x²)

Hope this helps :)

5 0
4 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B2.568%20%5Ctimes%205.8%7D%7B4.186%7D%20" id="TexFormula1" title=" \frac{2.568 \ti
melomori [17]
Using a calculator:

(2.568 x 5.8)/4.186 = 3.5581460…
= 3.56 (3sf)

You didn’t specify the correct number of significant figures needed.
3 0
3 years ago
A second-order reaction has a rate law: rate = k[a]2, where k = 0.150 m−1s−1. If the initial concentration of a is 0.250 m, what
Cerrena [4.2K]

Rate law for the given 2nd order reaction is:

Rate = k[a]2

Given data:

rate constant k = 0.150 m-1s-1

initial concentration, [a] = 0.250 M

reaction time, t = 5.00 min = 5.00 min * 60 s/s = 300 s

To determine:

Concentration at time t = 300 s i.e. [a]_{t}

Calculations:

The second order rate equation is:

1/[a]_{t} = kt +1/[a]

substituting for k,t and [a] we get:

1/[a]t = 0.150 M-1s-1 * 300 s + 1/[0.250]M

1/[a]t = 49 M-1

[a]t = 1/49 M-1 = 0.0204 M

Hence the concentration of 'a' after t = 5min is 0.020 M



7 0
4 years ago
The thin muscular wall that separates the right side of the heart from the left side is called the​
Lina20 [59]
The upper chambers are called the left and right atria, and the lower chambers are called the left and right ventricles. A wall of muscle called the septum separates the left and right atria and the left and right ventricles
8 0
3 years ago
Find the amount in grams of 2.0 x 10^23 atoms Cu
-Dominant- [34]

Answer:

21.182 g

Explanation:

There are about (6.0)(10^23) atoms in one mole of a substance, so the given sample has about 0.333 mol of Cu.

The atomic mass of Cu is 63.546 g/mol, meaning that the answer is about <u>21.182</u><u> </u><u>g</u>

5 0
2 years ago
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