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12345 [234]
4 years ago
7

What is hydrostatic equilibrium in a star? a) The balance between radiation from the surface and the rotation rate b) The expans

ion of the core when it is heated c) The increase in the rate of fusion when the star runs out of hydrogen d) The balance between the force of gravity directed in and thermal pressure directed.
Physics
1 answer:
Dahasolnce [82]4 years ago
6 0

Answer: d) The balance between the force of gravity directed in and thermal pressure directed

Explanation:

Hydrostatic Equilibrium helps to put in perspective star as self- regulating systems . It makes it plain that the energy generated in the star's hot core, is carried outward towards the cooler surface.

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Newton observed the action of a prism on white light and on red light. Because he (did or did not) control the event, this inves
natulia [17]
Newton observed the action of a prism on the white light and on red light. Because he did not control the event, this investigation of light was an observational study.

Hope this helps! (:
3 0
4 years ago
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A student standing on a stationary skateboard tosses a textbook with a mass of mb = 1.25 kg to a friend standing in front of him
juin [17]

Answer:

The velocity of the student has after throwing the book is 0.0345 m/s.

Explanation:

Given that,

Mass of book =1.25 kg

Combined mass = 112 kg

Velocity of book = 3.61 m/s

Angle = 31°

We need to calculate the magnitude of the velocity of the student has after throwing the book

Using conservation of momentum along horizontal  direction

m_{b}v_{b}\cos\theta= m_{c}v_{c}

v_{s}=\dfrac{m_{b}v_{b}\cos\theta}{m_{c}}

Put the value into the formula

v_{c}=\dfrac{1.25\times3.61\times\cos31}{112}

v_{c}=0.0345\ m/s

Hence, The velocity of the student has after throwing the book is 0.0345 m/s.

3 0
3 years ago
Water freezes at _____. 273°c -273°c 273 k -273 k
AURORKA [14]
273 k hope this helps :)
6 0
3 years ago
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Convert 1600.0m to km
Dominik [7]
The answer should be 1.6 kilometers.
3 0
3 years ago
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A moon orbits a planet every 42 hours with a mean orbital radius of .002819 AU. The mass of the moon is 8.932 x 1022 kg. Using N
Pepsi [2]

Answer:

The mass of the planet  is 1.9407\times10^{27}\ kg

Explanation:

Given that,

Time period = 42 hours = 151200 sec

Orbital radius = 0.002819 AU = 421716397.5 m

Mass of moon m=8.932\times10^{22}\ kg

We need to calculate the mass of the planet

Using Kepler’s third law

T^2\propto a^3

T^2=\dfrac{4\pi^2}{G(M+m)}\times a^3

Where, a = orbital radius

T = time period

G = gravitational constant

M = mass of moon

m = mass of planet

Put the value into the formula

(151200)^2=\dfrac{4\pi^2}{6.673\times10^{-11}(8.932\times10^{22}+m)}\times(421716397.5)^3

(8.932\times10^{22}+m)=\dfrac{4\pi^2}{6.673\times10^{-11}}\times\dfrac{(421716397.5)^3}{(151200)^2}

(8.932\times10^{22}+m)=1.94087\times10^{27}

m=1.94087\times10^{27}-8.932\times10^{22}

m=1.9407\times10^{27}\ kg

Hence, The mass of the planet  is 1.9407\times10^{27}\ kg

8 0
4 years ago
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