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3 years ago

I NEED HELP ASAP

1 answer:

8 0

<span>The definitions of the principal axis, centre of curvature , radius of curvature , and the vertex , of a convex mirror are analogous to the corresponding definitions for a concave mirror. </span>

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Two guitarists attempt to play the same note of wavelength 6.50 cm at the same time, but one of the instruments is slightly out

PolarNik [594]

Answer:

The two value of the wavelength for the out of tune guitar is

$\lambda _2 = (6.48,6.52) \ cm$

Explanation:

From the question we are told that

The wavelength of the note is $\lambda = 6.50 \ cm = 0.065 \ m$

The difference in beat frequency is $\Delta f = 17.0 \ Hz$

Generally the frequency of the note played by the guitar that is in tune is

$f_1 = \frac{v_s}{\lambda}$

Where $v_s$ is the speed of sound with a constant value $v_s = 343 \ m/s$

$f_1 = \frac{343}{0.0065}$

$f_1 = 5276.9 \ Hz$

The difference in beat is mathematically represented as

$\Delta f = |f_1 - f_2|$

Where $f_2$ is the frequency of the sound from the out of tune guitar

$f_2 =f_1 \pm \Delta f$

substituting values

$f_2 =f_1 + \Delta f$

$f_2 = 5276.9 + 17.0$

$f_2 = 5293.9 \ Hz$

The wavelength for this frequency is

$\lambda_2 = \frac{343 }{5293.9}$

$\lambda_2 = 0.0648 \ m$

$\lambda_2 = 6.48 \ cm$

For the second value of the second frequency

$f_2 = f_1 - \Delta f$

$f_2 = 5276.9 -17$

$f_2 = 5259.9 Hz$

The wavelength for this frequency is

$\lambda _2 = \frac{343}{5259.9}$

$\lambda _2 = 0.0652 \ m$

$\lambda _2 = 6.52 \ cm$

8 0

3 years ago

A +5.0 uC point charge is placed at the 0 cm mark of a meter stick and a -4.0 °C charge is

viva [34]

Answer:

-1.44*10^11v/m

Explanation:

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4 years ago

Physics !!!!!!!!!!!!

Nadya [2.5K]

Answer:

1. external force;not change

2. all of the above

Bonus!!!!!!

Can i have brainliest

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3 years ago

2H2+O2---> 2H2O can be classified as what type of reaction?

alisha [4.7K]

I believe the answer is B

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4 years ago

A car goes from 80 kn/h to 20 km/h in 0.5 h. What is the acceleration in km/h^2? *

jekas [21]

Answer:

<h2>In physics, acceleration is defined as the rate of change of the velocity of an object with respect to time. That is A = VF - VI /T; </h2><h2></h2><h2>Where A = Acceleration </h2><h2>VF = Final velocity = 20 km </h2><h2>VI = Initial velocity = 80 km </h2><h2>T= Time = 0.5 hr </h2><h2>A = (20 - 80)/ 0.5 = - 60/.5 </h2><h2>A = - 120 Km/ hr^2 </h2><h2></h2><h2>Therefore, the acceleration of the car is -120 km/hr^2. </h2><h2> Because the value is negative, the appropriate name that describe it is deceleration.</h2><h2>I Hope this helps</h2>

3 0

3 years ago