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marta [7]
3 years ago
10

PLLLLLLZ HELP 15 POINTS

Physics
1 answer:
amid [387]3 years ago
8 0
<h2>Option A is the correct answer.</h2>

Explanation:

A 10-ω resistor and a 30-ω resistor are connected in series across a 100-V battery

Total resistance = 10 + 30 = 40 ω

We have

            Voltage = Current x resistance

            100 = I x 40

              I = 2.5 A

In series current in all the resistors are same, that is 2.5 A

             Voltage in 10ω resistor, V = I x 10 = 2.5 x 10 = 25 V

In parallel connection potential in all the resistors are same.

             Voltage in 10ω resistor, V = 100 V

The ratio of the potential difference across the 10-ω resistor in the series combination to that of the 10-ω resistance connected in parallel = 25/100 = 1/4

Option A is the correct answer.

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two circular loops of wire, each containing a single turn, have the same radius of 4.0 cm and a common center. the planes of the
REY [17]

The magnetic field at center of circular loops of wire is 3.78 x 10¯⁵ T.

We need to know about the magnetic field at the center of circular loops of wire to solve this problem. The magnetic field at the center can be determined as

B = μ₀ . I / 2r

where B is magnetic field, μ₀ is vacuum permeability (4π×10¯⁷ H/m), I is the current and r is radius.

From the question above, we know that:

r = 4 cm = 0.04 m

I = 1.7 A

By substituting the parameter, we get

B = μ₀ . I / 2r

B = 4π×10¯⁷ . 1.7 / (2.0.04)

B = 2.67 x 10¯⁵ T

Due to the perpendicular plane of loops, the total magnetic field at center will be

Btotal = √(2(B²))

Btotal = √(2(2.67 x 10¯⁵²))

Btotal = 3.78 x 10¯⁵ T

Find more on magnetic field at: brainly.com/question/7802337

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3 0
1 year ago
What elements compose the stars and planets in the universe
Savatey [412]

Well hydrogen would be the main element, as a process called nuclear fusion with both helium and hydrogen atoms occurs within stars. And planets are the products of dead stars that have burned through their supplies of hydrogen, helium, and carbon. Planets are a product of this.

6 0
3 years ago
You observe a hockey puck of mass 0.12 kg, traveling across the ice at speed 18.3 m/sec. The interaction of the puck and the ice
Galina-37 [17]

The stopping distance is 143.1 m

Explanation:

First of all, we have to find the acceleration of the hockey puck. This can be done by using Newton's second law of motion:

\sum F =ma

where

\sum F = F_f = -0.14 N is the net force acting on the puck (the force of friction, negative because it acts in a direction opposite to the direction of motion)

m = 0.12 kg is the mass of the puck

a is the acceleration

Solving for a,

a=\frac{\sum F}{m}=\frac{-0.14}{0.12}=-1.17 m/s^2

The motion of the puck is a uniformly accelerated motion, therefore we can use the following suvat equation:

v^2-u^2=2as

where:

v = 0 is the final velocity (the puck comes to a stop)

u = 18.3 m/s is the initial velocity

a=-1.17 m/s^2 is the acceleration

s is the stopping distance

And solving for s, we find

s=\frac{v^2-u^2}{2a}=\frac{0-(18.3)^2}{2(-1.17)}=143.1 m

Learn more about accelerated motion:

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6 0
3 years ago
Charging an object without touching it is called?
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<span>Charging by induction</span>
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4 years ago
Balances are used to measure what a. Mass of an object b. Volume c. Force acting upon it d. Level surfaces on the table
suter [353]
<span>a. Mass of an object </span>
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