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hammer [34]
3 years ago
11

How can you tell that you’re driving in the right direction

Engineering
2 answers:
Lady bird [3.3K]3 years ago
7 0

Answer: if most people are driving the way that you are

Explanation:the law of the many

torisob [31]3 years ago
3 0
If people are driving towards you .
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Lets Try This: study the pictures. Describe what you see and think about it. write your answer on a sheet of paper. home room
Yuliya22 [10]

Answer: I see three children cleaning the lawn while one of them are raking the leaves and one is holding a dust pan. The other child is holding a bucket. On the other picture, i see a young boy watering plants.

BTW: these pictures are not very clear so answers may vary.

Explanation:

4 0
2 years ago
All of the following have the same units except: Group of answer choices resistance capacitive reactance. inductance. impedance.
Brilliant_brown [7]

Answer:

nnn

Explanation:

3 0
2 years ago
So in my settings i set it to send notifications too my email so ik when smtn happens but it doesn't even send stuff too it.....
attashe74 [19]

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3 0
4 years ago
Water flows through a converging pipe at a mass flow rate of 25 kg/s. If the inside diameter of the pipes sections are 7.0 cm an
ser-zykov [4K]

Answer:

volumetric flow rate = 0.0251 m^3/s

Velocity in pipe section 1 = 6.513m/s

velocity in pipe section 2 = 12.79 m/s

Explanation:

We can obtain the volume flow rate from the mass flow rate by utilizing the fact that the fluid has the same density when measuring the mass flow rate and the volumetric flow rates.

The density of water is = 997 kg/m³

density = mass/ volume

since we are given the mass, therefore, the  volume will be mass/density

25/997 = 0.0251 m^3/s

volumetric flow rate = 0.0251 m^3/s

Average velocity calculations:

<em>Pipe section A:</em>

cross-sectional area =

\pi \times d^2\\=\pi \times 0.07^2 = 3.85\times10^{-3}m^2

mass flow rate = density X cross-sectional area X velocity

velocity = mass flow rate /(density X cross-sectional area)

velocity = 25/(997 \times 3.85\times10^{-3}) = 6.513m/s

<em>Pipe section B:</em>

cross-sectional area =

\pi \times d^2\\=\pi \times 0.05^2= 1.96\times10^{-3}m^2

mass flow rate = density X cross-sectional area X velocity

velocity = mass flow rate /(density X cross-sectional area)

velocity = 25/(997 \times 1.96\times10^{-3}) = 12.79m/s

7 0
3 years ago
At what stage of development is an engineering team the most productive?
Alexxx [7]

Answer:

A

Explanation:

A because you are continuing to keep moving and thinking.

3 0
3 years ago
Read 2 more answers
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