Answer:
The maximum theoretical height that the pump can be placed above liquid level is ![\Delta h=9.975\,m](https://tex.z-dn.net/?f=%5CDelta%20h%3D9.975%5C%2Cm)
Explanation:
To pump the water, we need to avoid cavitation. Cavitation is a phenomenon in which liquid experiences a phase transition into the vapour phase because pressure drops below the liquid's vapour pressure at that temperature. As a liquid is pumped upwards, it's pressure drops. to see why, let's look at Bernoulli's equation:
![\frac{\Delta P}{\rho}+g\, \Delta h +\frac{1}{2} \Delta v^2 =0](https://tex.z-dn.net/?f=%5Cfrac%7B%5CDelta%20P%7D%7B%5Crho%7D%2Bg%5C%2C%20%5CDelta%20h%20%2B%5Cfrac%7B1%7D%7B2%7D%20%20%5CDelta%20v%5E2%20%3D0)
(
stands here for density,
for height)
Now, we are assuming that there aren't friction losses here. If we assume further that the fluid is pumped out at a very small rate, the velocity term would be negligible, and we get:
![\frac{\Delta P}{\rho}+g\, \Delta h =0](https://tex.z-dn.net/?f=%5Cfrac%7B%5CDelta%20P%7D%7B%5Crho%7D%2Bg%5C%2C%20%5CDelta%20h%20%20%3D0)
![\Delta P= -g\, \rho\, \Delta h](https://tex.z-dn.net/?f=%5CDelta%20P%3D%20-g%5C%2C%20%5Crho%5C%2C%20%5CDelta%20h)
This means that pressure drop is proportional to the suction lift's height.
We want the pressure drop to be small enough for the fluid's pressure to be always above vapour pressure, in the extreme the fluid's pressure will be almost equal to vapour pressure.
That means:
![\Delta P = 2.34\,kPa- 100 \,kPa = -97.66 \, kPa\\](https://tex.z-dn.net/?f=%5CDelta%20P%20%3D%202.34%5C%2CkPa-%20100%20%5C%2CkPa%20%3D%20-97.66%20%5C%2C%20kPa%5C%5C)
We insert that into our last equation and get:
![\frac{ \Delta P}{ -g\, \rho\,}= \Delta h\\\Delta h=\frac{97.66 \, kPa}{998 kg/m^3 \, \, 9.81 m/s^2} \\\Delta h=9.975\,m](https://tex.z-dn.net/?f=%5Cfrac%7B%20%5CDelta%20P%7D%7B%20-g%5C%2C%20%5Crho%5C%2C%7D%3D%20%5CDelta%20h%5C%5C%5CDelta%20h%3D%5Cfrac%7B97.66%20%5C%2C%20kPa%7D%7B998%20kg%2Fm%5E3%20%5C%2C%20%5C%2C%209.81%20m%2Fs%5E2%7D%20%5C%5C%5CDelta%20h%3D9.975%5C%2Cm)
And that is the absolute highest height that the pump could bear. This, assuming that there isn't friction on the suction pipe's walls, in reality the height might be much less, depending on the system's pipes and pump.
Answer:
Plastic deformation, irreversible or permanent. Deformation mode in which the material does not return to its original shape after removing the applied load. This happens because, in plastic deformation, the material undergoes irreversible thermodynamic changes by acquiring greater elastic potential energy.
Elastic deformation, reversible or non-permanent. the body regains its original shape by removing the force that causes the deformation. In this type of deformation, the solid, by varying its tension state and increasing its internal energy in the form of elastic potential energy, only goes through reversible thermodynamic changes.
The reason why giant stars become planetary nebulas is Supergiant stars do not have enough mass to generate the gravity necessary to cause a planetary nebula.
<h3>Why do giant stars become planetary nebulae?</h3>
A planetary nebula is known to be formed or created by a dying star. A red giant is known to be unstable and thus emit pulses of gas that is said to form a sphere around the dying star and thus they are said to be ionized by the ultraviolet radiation that the star is known to releases.
Learn more about giant stars from
brainly.com/question/27111741
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Answer:
cant see the moon sorry dude
Answer:
Chemical Engineer,Geological Engineer,Aerospace Engineer
Explanation: