Three resistors are connected into the section of a circuit described by the diagram. At which labeled point or points of the ci
rcuit could a fourth resistor be added in series with R1?
1 answer:
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Explanation:
The given data is as follows.
q = 6.0 nC =
inner radius (r) = 1.0 cm = 0.01 m (as 1 cm = 100 m)
So, there will be same charge on the inner surface as the charge enclosed with an opposite sign.
Formula to calculate the charge density is as follows.
.......... (1)
Since, area of the sphere is as follows.
A = ........... (2)
Hence, substituting equation (2) in equation (1) as follows.
=
=
or, = 4.77
Thus, we can conclude that the resulting charge density on the inner surface of the conducting sphere is 4.77 .
Answer:
Hey mate I shall not tell you the answer I shall explain it to you after this if still you can't understand then say
Explanation:
Derive v = u + at by Graphical Method. Consider the velocity – time graph of a body shown in the below Figure
Derive s = ut + (1/2) at2 by Graphical Method. Velocity so time graph to derive the equations of motion.
Derive v2 = u2 + 2as by Graphical Method. Velocity–Time graph to derive the equations of motion.
I hope you understand now
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