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Stells [14]
4 years ago
13

Plants grow over time by balancing two chemical reactions: photosynthesis and cellular respiration. Plants use the products of p

hotosynthesis as the reactants of cellular respiration.
Photosynthesis: 6CO2 + 6H2O + energy C6H12O6 + 6O2
Which is the chemical equation representing cellular respiration?
A. 6H2O + energy C6H12O6 + 6O2
B. C6H12O6 + 6O2 6CO2 + energy
C. 6CO2 + 6H2O + energy C6H12O6 + 6O2
D. C6H12O6 + 6O2 6CO2 + 6H2O + energy

Physics
1 answer:
Andreyy894 years ago
8 0
The answer to that I think would be D because:

A is wrong because it doesn't make sense the way the order it is in,

B doesn't make sense because it is in the wrong order,  and

C says the same exact thing that photosynthesis says which would mean that it is representing the photosynthesis equation not the chemical equation for cellular respiration.

Also it is D because D shows the correct way that the chemical equation representing cellular respiration is supposed to be in.

Hope this helped!

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When cattle are processed, what is the most likely use for the animals' skin?
galben [10]

When cattle are processed, the most likely use for the animals' skin is in

the production of Leather.

<h3 /><h3>Animals used for Leather production</h3>
  • Cattle
  • Goat
  • Crocodile etc.

The commonly used animals in leather production is however cattle and

they amount for a large percentage of leather present today. They also

involve various techniques such as tanning and crusting to ensure

conversion to leather.

Read more about Leather here brainly.com/question/2494725

3 0
3 years ago
I am desperate to get to Denver, Colorado to catch the Denver Broncos
Pavlova-9 [17]

Answer:

<em>The average speed needed is 68.4 mi/h</em>

Explanation:

<u>Average Speed </u>

If an object travels a distance d in a time t regardless of the direction, the average speed is the quotient of the distance over the time:

\displaystyle V=\frac{d}{t}

The distance to get to Denver from the Hamilton Street Campus is d=1,778 miles. An estimated time of t=26 hours should be needed to cover that distance, thus you will need to travel at an average speed of:

\displaystyle V=\frac{1,778\ mi}{26\ h}

V = 68.4 mi/h

The average speed needed is 68.4 mi/h

6 0
3 years ago
Suppose a 1 Gbps point-to-point link is being set up between the Earth and a new lunar colony. The distance from the moon to Ear
vagabundo [1.1K]

Answer:

The time required to send the data from Earth to Moon will be 1.28s while for a two way communication, to send it back to the earth, it will take double time i.e. <em>RTT = 2.56s </em>

Explanation:

Distance between Earth and Moon = 385,000 km = 3.85 x 10⁸m

Speed of data travel = speed of light ≈ 3 x 10⁸m/s

As, v=d/t

t=d/v

t=\frac{3.85*10^{8} }{3*10^{8}}

t=1.28s

RTT = Double of single way time taken = 2x1.28

<em><u>RTT=2.56s</u></em>

7 0
3 years ago
An aircraft is at a standstill. It accelerates to 140kts in 28 seconds. The aircraft weighs 28,000 lbs. How many feet of runway
stiv31 [10]

Answer:

runway use is 3307.8 feet

Explanation:

given data

velocity = 140 kts = 140 × 0.5144 m/s = 72.016 m/s

time = 28 seconds

weight = 28000 lbs

to find out

How many feet of runway was used

solution

we will use here first equation of motion for find acceleration

v = u + at     ..............1

here v is velocity given and u is initial velocity that is 0 and a is acceleration and t is time

put here value in equation 1

72.016 = 0 + a(28)

a = 2.572 m/s²

and

now apply third equation of motion

s = ut + 0.5×a×t²    .......................2

here s is distance and u is initial speed and t is time and a is acceleration

put here all value in equation 2

s = 0 + 0.5×2.572×28²  

s = 1008.24 m = 3307.8 ft

so  runway use is 3307.8 feet

5 0
3 years ago
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5 0
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