When cattle are processed, the most likely use for the animals' skin is in
the production of Leather.
<h3 /><h3>Animals used for Leather production</h3>
The commonly used animals in leather production is however cattle and
they amount for a large percentage of leather present today. They also
involve various techniques such as tanning and crusting to ensure
conversion to leather.
Read more about Leather here brainly.com/question/2494725
Answer:
<em>The average speed needed is 68.4 mi/h</em>
Explanation:
<u>Average Speed
</u>
If an object travels a distance d in a time t regardless of the direction, the average speed is the quotient of the distance over the time:

The distance to get to Denver from the Hamilton Street Campus is d=1,778 miles. An estimated time of t=26 hours should be needed to cover that distance, thus you will need to travel at an average speed of:

V = 68.4 mi/h
The average speed needed is 68.4 mi/h
Answer:
The time required to send the data from Earth to Moon will be 1.28s while for a two way communication, to send it back to the earth, it will take double time i.e. <em>RTT = 2.56s </em>
Explanation:
Distance between Earth and Moon = 385,000 km = 3.85 x 10⁸m
Speed of data travel = speed of light ≈ 3 x 10⁸m/s
As, v=d/t
t=d/v

t=1.28s
RTT = Double of single way time taken = 2x1.28
<em><u>RTT=2.56s</u></em>
Answer:
runway use is 3307.8 feet
Explanation:
given data
velocity = 140 kts = 140 × 0.5144 m/s = 72.016 m/s
time = 28 seconds
weight = 28000 lbs
to find out
How many feet of runway was used
solution
we will use here first equation of motion for find acceleration
v = u + at ..............1
here v is velocity given and u is initial velocity that is 0 and a is acceleration and t is time
put here value in equation 1
72.016 = 0 + a(28)
a = 2.572 m/s²
and
now apply third equation of motion
s = ut + 0.5×a×t² .......................2
here s is distance and u is initial speed and t is time and a is acceleration
put here all value in equation 2
s = 0 + 0.5×2.572×28²
s = 1008.24 m = 3307.8 ft
so runway use is 3307.8 feet
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