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Elena-2011 [213]
3 years ago
14

Why are photopolymers essential for stereolithography?

Engineering
1 answer:
Leokris [45]3 years ago
5 0

Answer:

They essential for the formation of layers in a 3-D model.

Explanation:

Stereolithography is 3D printing process in which a 3D model can be created. In stereolithography technology, there is vat of the UV curable photopolymer which is placed below in lower compartment of machine.

<u>When the machine begins to construct 3D model by the scanning and the  building of one layer at one time. Each layer in the model is constructed with UV laser and as laser traces next layer of object material hardens on contact.  </u>

Once layer is complete, platform slips down to make room for next layer. This is how, a model is created.

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A liquid stream containing 52.0 mole% benzene and the balance toluene at 20.0°C is fed to a continuous single-stage evaporator a
OLga [1]

Answer:

Operating Pressure P = 793.716 mmHg

Y_Benzene y1 = 0.541

Explanation:

Given that;

liquid phase leaving the evaporator = 32.5 mole%

Equi Temp T = 99.0°C = 99 + 273.15 = 372.15 K

Now let 1 and 2 represent Benzene and Toluene respectively.

Antoine's Constant for these components are;

COMPONENETS        A                B                    C

Benzene 1             4.72583     1660.652        -1.461

Toluene  2            4.07827     1343.943         -53.773

Antoine's equation is expressed as;

Ps = 10^(A - (B/(T+C)))

Ps is in Bar and T is in Kelvin

so

P1s = 10^( 4.72583 - (1660.652/(372.15 - (-1.461)))) = 1.7617 Bar

P2s = 10^( 4.07827 - (1343.943/(372.15 - (-53.773)))) = 0.7195 Bar

now here, liquid leaving and vapor are both in equilibrium

composition of liquid leaving are;

X1 = 32.5%    = 0.325

X2 = 1 - X1 = 1 - 0.325 = 0.675

Now

Raoult's Law is expressed as;

p × y1=x1 × pis     for all components

So for Benzene ; p × y1=x1 × p1s   ------let this be equation 1

for Toluene ; p × y2=x2 × p2s   ------let this be equation 2

lets add equ 1 and 2

p × y1=x1 × p1s + p × y2=x2 × p2s

p(y1 + y2) = x1 × p1s + x2 × p2s

buy y1 + y2 = 1

therefore we substitute

p(1) = 0.325 × 1.7617 + 0.675 × 0.7195 = 1.0582 Bar

we know that 1 Bar = 750.062 mmHg

so p = 1.0582 × 750.062

p = 793.716 mmHg

Also from equation 1

p × y1=x1 × p1s

y1 = (x1 × p1s) / p

y1 = (0.325 × 1.7617) / 1.0582

y1 = 0.541

Therefore;

Operating Pressure P = 793.716 mmHg

Y_Benzene y1 = 0.541

5 0
3 years ago
The $500 Jamie must pay is called
omeli [17]

Answer:

a bill

Explanation:

8 0
4 years ago
<img src="https://tex.z-dn.net/?f=%5Cint%5Climits%5Ea_b%20%7B7x%7D%20%5C%2C%20dx" id="TexFormula1" title="\int\limits^a_b {7x} \
Dafna11 [192]

Answer:

\frac{7}{2}a^2 - \frac{7}{2}b^2

Explanation:

\int\limits^a_b {7x} \, dx

=[\frac{7}{2}x^2]^a_b

=\frac{7}{2}a^2 - \frac{7}{2}b^2

5 0
3 years ago
True or false most of the time engineers need to optimize their inventions and innovations
Nostrana [21]

Answer:

True

Explanation:

BecUse it true its obvious

4 0
3 years ago
During the design of most real-world networks, you’ll discover that using more than one type of networking medium is common. The
rusak2 [61]

Answer:

A.Fiber optics are the best option. Because of the fact they transmit signals as light instead of current, fibres are immune to electronic magnetic interference(EMI) and to radio-frequency (RFI). We can connect the fiber ends to the 10BaseT networks by switches, to the design shop and other end to the front office. Since it's optic based, signals from the shop floor can easily be carried where EMI and RFI are enormous. Shielded Twisted Pairs can also minize the interference, but is not recommended, because they are not close to efficiency in comparison with optical fibres.

B. The 10Base5 Coax cable is a good choice for question 2. It is 500 m long and also less expensive. However, the downside is that it is an old and interferential technology. Multimode fiber with maximum data rates of up to 10 Gbps per second over a 600 meter distance may be the other best choice. So, either fiber optics or 10Base5 are available to you.

C. In the elevator shaft, we can use RISER CAT6 cable or 802.11n Wireless Access Point. The second part says of the "higher speed" requirement, so that the WAP of 802.11n is obvious. RISAR CAT6 or Fiber Optics (if we look for any interfaces in the elevator shaft) can be the best choice.

3 0
3 years ago
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