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3 years ago

Why are photopolymers essential for stereolithography?

Engineering

1 answer:

Leokris [45]3 years ago

5 0

Answer:

They essential for the formation of layers in a 3-D model.

Explanation:

Stereolithography is 3D printing process in which a 3D model can be created. In stereolithography technology, there is vat of the UV curable photopolymer which is placed below in lower compartment of machine.

<u>When the machine begins to construct 3D model by the scanning and the building of one layer at one time. Each layer in the model is constructed with UV laser and as laser traces next layer of object material hardens on contact. </u>

Once layer is complete, platform slips down to make room for next layer. This is how, a model is created.

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viktelen [127]

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3 0

3 years ago

Read 2 more answers

A pin must be inserted into a collar of the same steel using an expansion fit. The coefficient of thermal expansion of the metal

nirvana33 [79]

Answer:

a) the temperature to which the pin must be cooled for assembly is $T_2 = -101.89^ \ ^0}C$

b) the radial pressure at room temperature after assembly is $P_f = 62.8 \ MPa$

c) the safety factor in the resulting assembly = 6.4

Explanation:

Coefficient of thermal expansion $\alpha = 12.3*10^{-6} \ ^0 C$

Yield strength $\sigma_y$ = 400 MPa

Modulus of elasticity (E) = 209 GPa

Room Temperature $T_1$ = 20°C

outer diameter of the collar $D_o = 95 \ mm$

inner diameter of the collar $D_i = 60 \ mm$

pin diameter $D_p$ = $60.03 \ mm$

Clearance c = 0.06 mm

The temperature to which the pin must be cooled for assembly can be calculated by using the formula:

$(D_i - c )-D_p = \alpha * D_p(T_2-T_1)$

$(60-0.06)-60.03=12.3*10^{-6}*60.03(T_{2}-20^{0}C)$

-0.09 = $7.38369*10^{-4}$ $(T_{2}-20^{0}C)$

-0.09 = $7.38369*10^{-4}T_2$ $\ \ - \ \ 0.01476738$

$-0.09 + 0.01476738$ = $7.38369*10^{-4}T_2$

−0.07523262 = $7.38369*10^{-4}T_2$

$T_2 = \frac{-0.07523262}{7.38369*10^{-4}}$

$T_2 = -101.89^ \ ^0}C$

To determine the radial pressure at room temperature after assembly ;we have:

$P_f = \frac{E * (D_p-D_i)(D_o^2-D_1^2)}{D_i*D_o} \\ \\ \\ P_f = \frac{209*10^9* 0.03(95^2-60^2)}{60*95^2} \\ \\ P_f = 62815789.47 \ Pa \\ \\ P_f = 62.8 \ MPa$

c) the safety factor of the resulting assembly is calculated as:

safety factor = $\frac{Yield \ strength }{walking \ stress}$

safety factor = $\frac{400}{62.8}$

safety factor = 6.4

Thus, the safety factor in the resulting assembly = 6.4

4 0

3 years ago

2.5 kg of air at 150 kPa and 12°C is contained in a gas-tight, frictionless piston-cylinder device. The air is now compressed to

Korolek [52]

Answer:

Work input =283.47 KJ

Explanation:

Given that

$P_1=150\ KPa$

$P_2=600\ KPa$

T=12°C=285 K

m= 2.5 kg

Given that this is the constant temperature process.

e know that work for isothermal process

$W=P_1V_1\ln \dfrac{P_1}{P_2}$

$W=mRT\ln \dfrac{P_1}{P_2}$

So now putting the values

$W=mRT\ln \dfrac{P_1}{P_2}$

$W=2.5\times 0.287\times 285\ln \dfrac{150}{600}$

W=-283.47 KJ

Negative sign indicates that work is done on the system.

So work input =283.47 KJ

8 0

3 years ago

CNG is a readily available alternative to

Veseljchak [2.6K]

Answer:

Basics. CNG is a readily available alternative to gasoline that's made by compressing natural gas to less than 1% of its volume at standard atmospheric pressure. ... Expanding the numbers of CNG fueling stations would allow for the increase of CNG vehicles on U.S. roads.

3 0

3 years ago

A fluid has a viscosity of 13 P and a specific gravity of 0.94. Determine the kinematic viscosity of this fluid in units of ft²/

OlgaM077 [116]

Answer:

kinematic viscosity is 0.0149 ft²/s

Explanation:

given data

specific gravity S = 0.94

density ρ = 0.94 × 1000

viscosity μ = 13 Poise = 1.3 Pa-sec

we know 1 poise = 0.1 pas

to find out

kinematic viscosity

solution

we will apply here Kinematic viscosity formula that is

kinematic viscosity = $\frac{\mu}{\rho}$ ..................1

put here value in equation 1

and here ρ is density and μ is viscosity

kinematic viscosity = $\frac{1.3}{0.94*1000}$

kinematic viscosity = 1.382978 × $10^{-3}$ m³/s

so kinematic viscosity is 0.0149 ft²/s

3 0

3 years ago