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fiasKO [112]
4 years ago
6

If the stopping sight distance required to avoid colliding with a fallen boulder on a mountain pass is 800 feet, what is the lik

ely grade of the mountainous segment of roadway. Assume a perception-reaction time of 2.5 seconds, a design speed of 65 miles per hour, and an a/g value equal to 0.35. [Use Practical Stopping Distance]
Engineering
1 answer:
Anettt [7]4 years ago
5 0

Answer:

Grade is 10.32%

Explanation:

Given data:

stopping side distance is 800ft

t = 2.5 sec

design speed v = 65 miles/hr

a/g value is 0.35

stopping side distance is SSD

SSD = 1.47 vt + \frac{v^2}{30(a/g - G}

plugging all value for G

800 = 1.47 \times 65\times 2.4 + \frac{65^2}{30(0.35 -G)}

800 - 229.32 = \frac{65^2}{30(0.35 -G)}

570.68 = \frac{65^2}{30(0.35 -G)}

G = 0.1032

Grade is 10.32%

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when S < 100%, the soil is partially saturated, and this will give the lower limit of water content.

Note; S = 0% means that the soil is perfectly dry. Hence, when s = 1 will give the lowest limit of water content.

To get the relationship between water content and saturation, we will manipulate the equations above;

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putting eqn. (6) into (5)

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Again, from eqn (1)

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substituting into eqn. (7)

w = \frac{V_w}{\frac{V_v}{e}{G_s} } = \frac{V_w e}{V_vG_s} \\ but \frac{V_w}{V_v}  = S

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mass of water = P_wV_w= 1 * 45 = 45_{g}

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