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mylen [45]
4 years ago
8

Two aircraft rivets, one of iron and the other of copper, are placed in a calorimeter that has an initial temperature of 10°c.

the data for the metals are as follows: iron copper mass(g) 39.0 13.0 initial t (°c) 0.0 100.0 c(j/g·k) 0.450 0.387 (a) will heat flow from fe to cu or from cu to fe? cu to fe fe to cu (b) to determine the actual final temperature, what must be known? the volume of the calorimeter the heat capacity of the calorimeter the density of the metals
Chemistry
2 answers:
Dominik [7]4 years ago
8 0

a) Copper is at a higher temperature, so the flow of heat will take place from copper to iron. Heat is a form of energy, which always flows from higher temperature to lower temperature.  

b) To determine the actual final temperature, the heat capacity of the calorimeter must be known. A calorimeter constant refers to a constant, which quantifies the heat capacity of a calorimeter. It may be determined by using a known amount of heat to the calorimeter and measuring the corresponding change in temperature of the calorimeter.  


juin [17]4 years ago
6 0

Answer:

(a) Cu to Fe

(b) heat capacity of the calorimeter

Explanation:

<em>(a) Will heat flow from Fe to Cu or from Cu to Fe?</em>

We need to consider the initial temperatures:

Cu 100.0°C

Fe 0.0 °C

Calorimeter 10 °C

Heat flows from bodies with higher temperatures to bodies with lower temperatures. So, heat will flow from Cu to Fe and to the calorimeter.

<em>(b) To determine the actual final temperature, what must be known?</em>

To determine the final temperature of the system, we need to know the amount of heat absorbed by the calorimeter (Qcal). We can calculate it using the following expression.

Qcal = C . ΔT

where,

C: heat capacity of the calorimeter

ΔT: change in the temperature

Thus, we need to know the heat capacity of the calorimeter.

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How to draw Hess' Cycle for this question ?
NISA [10]

Answer : The standard enthalpy of formation of ethylene is, 51.8 kJ/mole

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The formation reaction of C_2H_4 will be,

2C(s)+2H_2(g)\rightarrow C_2H_4(g)    \Delta H_{formation}=?

The intermediate balanced chemical reaction will be,

(1) C_2H_4(g)+3O_2(g)\rightarrow 2CO_2(g)+2H_2O(l)     \Delta H_1=-1411kJ/mole

(2) C(s)+O_2(g)\rightarrow CO_2(g)    \Delta H_2=-393.7kJ/mole

(3) H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(l)    \Delta H_3=-285.9kJ/mole

Now we will reverse the reaction 1, multiply reaction 2 and 3 by 2 then adding all the equations, we get :

(1) 2CO_2(g)+2H_2O(l)\rightarrow C_2H_4(g)+3O_2(g)     \Delta H_1=+1411kJ/mole

(2) 2C(s)+2O_2(g)\rightarrow 2CO_2(g)    \Delta H_2=2\times (-393.7kJ/mole)=-787.4kJ/mole

(3) 2H_2(g)+2O_2(g)\rightarrow 2H_2O(l)    \Delta H_3=2\times (-285.9kJ/mole)=-571.8kJ/mole

The expression for enthalpy of formation of C_2H_4 will be,

\Delta H_{formation}=\Delta H_1+\Delta H_2+\Delta H_3

\Delta H=(+1411kJ/mole)+(-787.4kJ/mole)+(-571.8kJ/mole)

\Delta H=51.8kJ/mole

Therefore, the standard enthalpy of formation of ethylene is, 51.8 kJ/mole

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