The electric field between square plates of a parallel-plate capacitor has magnitude E. The potential across the plates is maint
ained with constant voltage by a battery as they are pulled apart to twice their original separation, which is small compared to the dimensions of the plates. The magnitude of the electric field between the plates is now equal to a)E b)E/4 c)E/2 d)4E e)2E
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The vertical component of the initial velocity is
The horizontal component of the initial velocity is
The horizontal displacement when the object reaches maximum height is
The given parameters;
the horizontal displacement of the object, = x
the vertical displacement of the object, = y
acceleration due to gravity, = g
time of motion, = t
The vertical component of the initial velocity is given as;
The horizontal component of the initial velocity is calculated as;
The time to reach to the maximum height is calculated as;
The horizontal displacement when the object reaches maximum height is calculated as;
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Answer:
1317.4 m
Explanation:
We are given that
Angle=
Initial speed =
We have to find the horizontal distance covered by the shell after 5.03 s.
Horizontal component of initial speed=
Vertical component of initial speed=
Time=t=5.03 s
Horizontal distance =
Using the formula
Horizontal distance=
Horizontal distance=1317.4 m
Hence, the horizontal distance covered by the shell=1317.4 m