Answer:
(A) 10052.2 m/s²
(B) 0.00678 seconds
Explanation:
From the question,
(A) Applying
V² = U²+2as..................... Equation 1
Where V = Final velocity, U = Initial velocity, a = acceleration due to gravity, s = distance.
make a the subject of the equation
a = (V²-U²)/2s........................ Equation 2
Given: U = 0 m/s( from rest), V = 68 m/s, s = 0.230 m
Substitute these values into equation 2
a = (68²-0²)/(2×0.230)
a = 10052.2 m/s²
(B) Using,
a = (V-U)/t......................... Equation 3
Where t= time.
make t the subject of the equation
t = (V-U)/a......................... Equation 4
Given: V = 68 m/s, U = 0 m/s, a = 10052.2
Substitute into equation 4
t = (68-0)/10052.2
t = 0.00678 seconds
P₄ + 3O₂ ⟶ 2P₂O₃
Explanation:
A balanced equation is any equation that complies with the law of conservation of matter and mass.
The law of conservation of matter states that "in a chemical reaction, matter is neither created nor destroyed but simply rearranges. ".
This suggests that the total number of atoms on both reactant and product sides must be the same in a balanced chemical equation. Also, the same atoms are found on both sides of a chemical equation with no additional or external species.
Now let us check if the equation is conserved:
P₄ + 3O₂ ⟶ 2P₂O₃
Atoms reactant product
P 4 4
O 6 6
We see that we have equal number of atoms on both sides. The equation is balanced.
learn more:
Balanced equation brainly.com/question/2612756
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Answer:
The question lacks a photo to fully answer correctly
If the fossil has its neck bent backwards towards its back, that is the common way to which dinosaurs died.
If the fossil is scattered a bit from its other linking fossil pieces, than it is most likely that the dinosaur was a meal to a predator.
Fossils that are in array but are divided clearly at a section suggests that land moved. Possibly earthquake or Pangea took place.
We will use two definitions to solve this problem. The first will be given by the conservation of energy, whereby the change in kinetic energy must be equivalent to work. At the same time, work can be defined as the product between the force by the distance traveled. By matching these two expressions and clearing for the Force we can find the desired variable.
Thus the force acting on the sled is,
Replacing,
Therefore the Force acting on the sled is 32N
