let the mass of the two objects be m₁ and m₂ respectively and the distance between the two objects be "r₁" initially.
the gravitational force between the two objects initially is then given as
F₁ = G m₁ m₂ /r₁² eq-1
where G = universal gravitational constant
when the objects are moved closer and the distance between the objects become one third of the original distance, hence
r₂ = distance after objects moved closer = r₁/3
new gravitational force between the objects after they are moved closed is given as
F₂ = G m₁ m₂ /r₂² eq-2
dividing eq-2 by eq-1
F₂/F₁ = (G m₁ m₂ /r₂² )/(G m₁ m₂ /r₁²)
F₂/F₁ = r₁²/r₂²
we know that , r₂ = r₁/3
hence
F₂/F₁ = r₁²/(r₁/3)²
F₂/F₁ = 9
F₂ = 9 F₁
hence the gravitational force becomes nine times its initial value
Hello!
We can use Ohm's Law to solve for the potential difference across a resistor given the current and resistance:
V = Potential Difference (? V)
i = Current (1.5 A)
R = Resistance (12 Ω)
Plug in the known values and solve.
Work done in moving a proton = potential difference×Charge of a proton
= 164×1.6×10⁻¹⁹ = 2.624×10⁻¹⁷ J
This work done should be equal to change in kinetic energy.
Initial speed of proton is zero therefore K.E initial will be zero.
Work done = final kinetic energy = 2.624×10⁻¹⁷ J
K.E = mv²/2
v² = 2(2.624×10⁻¹⁷)/1.6×10⁻²⁷ = 3.28×10¹⁰ m/s
∴ v = 1.811×10⁵ m/s
Answer:
When a hammer strikes the closed end of a air filled tube it causes a transverse wave within the tube.
Explanation:
