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3 years ago

When the mover pushes the box, two equal forces result. explain why the box moves even though the forces are equal and opposite?

1 answer:

8 0

The reaction force from the box may be equal and opposite, but it does not act on the box, it acts on the person. The force exerted by the person is on the box. Therefore, despite the fact that the forces are equal and opposite, because they are not on the same object, motion occurs.

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Ryan applied a force of 10N and moved a book 30 cm in the direction of the force. How much was the workdone by Ryan?

Xelga [282]

<h2><u>Question</u><u>:</u><u>-</u></h2>

Ryan applied a force of 10N and moved a book 30 cm in the direction of the force. How much was the work done by Ryan?

<h2><u>Answer:</u><u>-</u></h2>

<h3>Given,</h3>

=> Force applied by Ryan = 10N

=> Distance covered by the book after applying force = 30 cm

30 cm = 0.3 m (distance)

=> Work done = Force × Distance

=> 10 × 0.3

=> 3 Joules

$\small \boxed{work \: done \: by \: Ryan \: = 3 \: Joules}$

4 0

3 years ago

Which parts of the graph would increase if all of earth's polar ice melts? Which part would decrease?

Sedbober [7]

Answer:

the answer to the question is the part that is reflected by clouds and atmosphere 26%

8 0

3 years ago

Please need help on this one

jolli1 [7]

Answer:

The second answer from the top, no the energy in the wave pushed the water particles from above the earthquake in the opposite direction.

Explanation:

I believe this is the correct answer. Hope you do well

4 0

3 years ago

Read 2 more answers

The two blocks in oscillate on a frictionless surface with a period of 1.5 s. The upper block just begins to slip when the ampli

Setler79 [48]

Answer:

0.72

Explanation:

$T$ = Time period of oscillation = 1.5 s

Angular frequency is given as

$w = \frac{2\pi }{T}\\w = \frac{2(3.14) }{1.5}\\w = 4.2 rad/s$

$A$ = Amplitude of oscillation = 40 cm = 0.40 m

$\mu$ = Coefficient of static friction = ?

$a$ = acceleration of the block

$m$ = mass of the block

Maximum acceleration of the block is given as

$a = Aw^{2}$

frictional force is given as

$f = \mu mg$

As per newton's second law

$f = ma \\\\\mu mg = ma \\\mu g = a\\\mu g = Aw^{2}\\\mu (9.8) = (0.40)(4.2)^{2}\\\mu = 0.72$

8 0

3 years ago

2. As a pendulum swings, its energy is constantly converted between kinetic

Alex

Answer:

at point F

Explanation:

To know the point in which the pendulum has the greatest potential energy you can assume that the zero reference of the gravitational energy (it is mandatory to define it) is at the bottom of the pendulum.

Then, when the pendulum reaches it maximum height in its motion the gravitational potential energy is

U = mgh

m: mass of the pendulum

g: gravitational constant

The greatest value is obtained when the pendulum reaches y=h

Furthermore, at this point the pendulum stops to come back in ts motion and then the speed is zero, and so, the kinetic energy (K=1/mv^2=0).

A) answer, at point F

6 0

3 years ago