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mr Goodwill [35]
3 years ago
8

When the mover pushes the box, two equal forces result. explain why the box moves even though the forces are equal and opposite?

Physics
1 answer:
Helga [31]3 years ago
8 0
The reaction force from the box may be equal and opposite, but it does not act on the box, it acts on the person. The force exerted by the person is on the box. Therefore, despite the fact that the forces are equal and opposite, because they are not on the same object, motion occurs.
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Why is Venus sometimes called Earth’s twin?
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B.

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Explanation:

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The barcoding process is helpful because it A. increases the security and accuracy of stored and dispensed medications. B. helps
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A model airplane with a mass of 0.741kg is tethered by a wire so that it flies in a circle 30.9 m in radius. The airplane engine
Tju [1.3M]

Answer:

_T}=24.57Nm

ω = 0.0347 rad/s²

a ≅ 1.07 m/s²

Explanation:

Given that:

mass of the model airplane = 0.741 kg

radius of the wire = 30.9 m

Force = 0.795 N

The torque produced by the net thrust about the center of the circle can be calculated as:

_T } = Fr

where;

F represent the magnitude of the thrust

r represent the radius of the wire

Since we have our parameters in set, the next thing to do is to replace it into the above formula;

So;

_T}=(0.795)*(30.9)

_T}=24.57Nm

(b)

Find the angular acceleration of the airplane when it is in level flight rad/s²

_T}=I \omega

where;

I = moment of inertia

ω = angular acceleration

The moment of inertia (I) can also be illustrated as:

I = mr^2

I = ( 0.741) × (30.9)²

I = 0.741 × 954.81

I = 707.51 Kg.m²

_T}=I \omega

Making angular acceleration the subject of the formula; we have;

\omega = \frac{_T}{I}

ω = \frac{24.57}{707.51}

ω = 0.0347 rad/s²

(c)

Find the linear acceleration of the airplane tangent to its flight path.m/s²

the linear acceleration (a) can be given as:

a =  ωr

a = 0.0347 × 30.9

a = 1.07223 m/s²

a ≅ 1.07 m/s²

5 0
3 years ago
The unique name given to each organism ; made up of Genus and species..is..?
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6 0
4 years ago
Two fans are watching a baseball game from different positions. One fan is located directly behind home plate, 18.3 mfrom the ba
hjlf

Answer:

Δt = 0.315s

Explanation:

To calculate the time difference, in which both fans hear the batterstrike, you first calculate the time which takes the sound to travel the distances to both fans:

t_1=\frac{d_1}{v_s}

t_2=\frac{d_2}{v_s}

d1: distance to the first fan = 18.3 m

d2: distance to the second fan = 127 m

vs: speed of sound = 345 m/s

You replace the values of the parameters to calculate t1 and t2:

t_1=\frac{18.3m}{345m/s}=0.053s\\\\t_2=\frac{127m}{345m/s}=0.368s

The difference in time will be:

\Delta t =t_2-t_2=0.368s-0.053s=0.315s

Hence, the time difference between hearing the sound at the location s of both fans is 0.315s

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