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Nitella [24]
2 years ago
14

The Flintstones and Rubbles decide to try out the new inclined bowling alley, ``Bedslant Bowling''. Betty's ball and Wilma's bal

l have the same size, but Wilma's ball is hollow. Fred's ball and Barney's ball are scaled down versions of Betty's ball and Wilma's ball respectively. They all place their bowling balls on the same pitch incline and release them from rest at the same time. Answer choices are (greater than, less than or equal to)
a) The time it takes for Wilma's ball to hit the pins is .... that for Barney's ball to hit.
b) The time it takes for Barney's ball to hit the pins is .... that for Fred's ball to hit.
c) The time it takes for Betty's ball to hit the pins is .... that for Fred's ball to hit.
d) The time it takes for Betty's ball to hit the pins is .... that for Barney's ball to hit.
e) The time it takes for Fred's ball to hit the pins is .... that for Wilma's ball to hit.
f) The time it takes for Wilma's ball to hit the pins is .... that for Betty's ball to hit.
Physics
1 answer:
bogdanovich [222]2 years ago
5 0

A

Explanation:

fred ball hit the pin the time for all just put a hit in his right knee and do not need to be on bed at the carbon footprint in his first year of practice at all but his teammates were also on bed and you were a good friend to be with you cute guys that he is the most likely and do you have the ability for you I don't want him on you and

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Zinc can not be changed into a simpler substance by a chemical or physical process. Therefore, zinc is classified as:
bonufazy [111]
The correct answer I think is a compound
7 0
3 years ago
When a perfume bottle is opened, some liquid changes to gas and the fragrance spreads around the room. Which sentence explains t
Katyanochek1 [597]
When a perfume bottle is opened, some liquid changes to gas and the fragrance spreads around the room because gases do not have a definite volume.

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5 0
3 years ago
1.a bag is dropped from a hovering helicopter. the bag has fallen for 2 s. what is the ball's velocity at the instant its hittin
omeli [17]

1. The bag's velocity immediately before hitting the ground.

Recall this kinematics equation:

Vf = Vi + aΔt

Vf is the final velocity, Vi is the initial velocity, a is the acceleration, and Δt is the time elapsed.

Given values:

Vi = 0m/s (you assume this because the bag is dropped, so it falls starting from rest)

a is 9.81m/s² (this is the near-constant acceleration of objects near the surface of the earth)

Δt = 2s

Plug in the values and solve for Vf:

Vf = 0 + 9.81×2

Vf = 19.62m/s

2. The height of the helicopter.

Recall this other kinematics equation:

d = ViΔt + 0.5aΔt²

d is the distance traveled by the object, Vi is the initial velocity, a is the acceleration, and Δt is the time elapsed.

Given values:

Vi = 0m/s (bag is dropped starting from rest)

a = 9.81m/s² (acceleration due to gravity of the earth)

Δt = 2s

Plug in the values and solve for d:

d = 0×2 + 0.5×9.81×2²

d = 19.62m

3. Time of the bag's fall and its velocity immediately before hitting the ground... if it started falling at 2m/s

Reuse the equation from question 2:

d = ViΔt + 0.5aΔt²

Given values:

d = 19.6m (height of the helicopter obtained from question 2)

Vi = 2m/s

a = 9.81m/s² (acceleration due to earth's gravity)

Plug in the values and solve for Δt:

19.6 = 2Δt + 0.5×9.81Δt²

4.91Δt² + 2Δt - 19.6 = 0

Use the quadratic formula to get values of Δt (a quick Google search will give you the formula and how to use it to solve for unknown values):

Δt = 1.8s, Δt = −2.2s

The formula gives us 2 possible answers for Δt but within the situation of our problem, only the positive value makes sense. Reject the negative value.

Δt = 1.8s

Now we can use this new value of Δt to get the velocity before hitting the ground:

Vf = Vi + aΔt

Given values:

Vi = 2m/s

a = 9.81m/s²

Δt = 1.8s (result from previous question)

Plug in the values and solve for Vf:

Vf = 2 + 9.81×1.8

Vf = 19.66m/s

4 0
3 years ago
Definiton of ionziation energy of an elemnt
inna [77]
Ionization energy<span> is the </span>energy<span> required to remove an electron from a gaseous </span>atom<span> or ion.</span>
3 0
3 years ago
A block slides down a frictionless incline with constant acceleration. After sliding 6.80 m down, it has a speed of 3.80 m/s. Wh
melisa1 [442]

Answer:

speed when the block had slid 3.40 m is 2.68 m/s

Explanation:

given data

distance = 6.80 m

speed = 3.80 m/s

to find out

speed when the block had slid 3.40 m

solution

we will apply here equation of motion that is

v²-u² = 2×a×s   ..............1

here s is distance, a is acceleration and v is speed and u is initial speed that is 0

so put here all value in equation 1 to get a

v²-u² = 2×a×s

3.80²-0 = 2×a×6.80

a = 1.06 m/s²

so

speed when distance 3.40 m

from equation 1 put value

v²-u² = 2×a×s

v²-0 = 2×1.06×3.40

v² = 7.208

v = 2.68

so speed when the block had slid 3.40 m is 2.68 m/s

7 0
3 years ago
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