Answer:
in the previous sections you have seen that any real number have been the symbol of expenses have asked to represent it on the number line literacy house suppose you want to locate on the number line we know that this line is between two entry so let us look closely at the portions of the number line between between 2 to 25 by 50 bye-bye 2.00 with this into 5
Answer:
please give brainliest my brother just got the corona virus
Explanation:
this is my brothers account he wants to get 5 brainliest
Answer:
Q = 378.247 Bt/hr
Explanation:
given data:
diameter of container = 3 m
so r = 1.5 m
T1 = 50°C
T2 = 100°C
depth y = 3 ft
Heat transfer is given as Q
Where
S = Shape factor for the object
S = 25.132 ft
Q = 25.132*0.301 *(100-50)
Q = 378.247 Bt/hr
Answer:
0.96kg/s
Explanation:
Hello! To solve this exercise we must use the first law of thermodynamics, which states that the sum of the energies that enter a system is the same amount that must go out. We must consider the following!
state 1 : is the first flow in the input of the chamber
h1=entalpy=335.02KJ/kg
m1=mass flow=0.56kg/s
state 2 : is the second flow in the input of the chamber
h2=entalpy=83.915KJ/kg
state 3:is the flow that comes out
h3=entalpy=175.90 kJ/kg
now use the continuity equation that states that the mass flow that enters is the same as the one that comes out
m1+m2=m3
now we use the first law of thermodynamics
m1h1+m2h2=m3h3
335.02m1+83.915m2=175.9m3
as the objective is to find the cold water mass flow(m2) we divide this equation by 175.9
1.9m1+0.477m2=m3
now we subtract the equations found in the equation of continuity and first law of thermodynamics
m1 + m2 = m3
-
1.9m1 + 0.477m2=m3
----------------------------------
-0.9m1+0.523m2=0
solving for m2
the mass flow rate of the cold-water is 0.96kg/s
Answer:
Explanation:
In order to know the value of the speed at any time t, we need to integrate the acceleration. Once we get the speed vs time, we need to integrate again to get the distance traveled by the motorcycle vs time. So let's start with the speed first:
We will integrate once again to get distance:
Now we just need t evaluate S(10s):
S(10) = 133.3m
For the acceleration, we know that:
where
and
So, finally: