Answer:
a) maximum wavelength for destructive interference = 220 m
b) maximum wavelength for constructive interference = 110 m
Explanation:
The antennas are placed such that
A ------110 m------ B --30 m-- Q
For destructive interference, the difference in path length of the waves from each antenna is related to the wavelength through.
(m + ½)λ = |d₁ - d₂|
For maximum wavelength, m = 0 and
(λ/2) = |d₁ - d₂|
And for Constructive interference, the difference in path length of the waves from the two antennas is related to the wavelength through
mλ = |d₁ - d₂|
For maximum wavelength, m = 0
λ = |d₁ - d₂|
d₁ = path length from Q to A = 110+30 = 140 m
d₂ = path length from Q to B = 30 m
|d₁ - d₂| = 140 - 30 = 110 m
So, maximum wavelength for destructive interference is given as
(λ/2) = |d₁ - d₂| = 110
λ = 110 × 2 = 220 m
maximum wavelength for Constructive interference is given as
λ = |d₁ - d₂| = 110
λ = 110 m
Hope this Helps!!!