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AVprozaik [17]
4 years ago
8

Describing Waves

Physics
2 answers:
Misha Larkins [42]4 years ago
6 0

Answer:

Screen Shot below

Explanation:

LiRa [457]4 years ago
3 0

Answer:Direct them straight across

Explanation:

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a ultrasonic wave at 8x10^4 Hz is emitted into a vien where the speed of sound in blood is 1570 m/s. the wave reflects off the r
Aneli [31]

Answer: 0.392 m/s

Explanation:

The Doppler shift equation is:

f'=\frac{V+V_{o}}{V-V_{s}} f

Where:

f=8(10)^{4} Hz is the actual frequency of the sound wave

f'=8.002(10)^{4} Hz is the "observed" frequency

V=1570 m/s is the speed of sound

V_{o}=0 m/s is the velocity of the observer, which is stationary

V_{s} is the velocity of the source, which are the red blood cells

Isolating V_{s}:

V_{s}=\frac{V(f'-f)}{f'}

V_{s}=\frac{1570 m/s(8.002(10)^{4} Hz-8(10)^{4} Hz)}{8.002(10)^{4} Hz}

Finally:

V_{s}=0.392 m/s

3 0
3 years ago
Pls help !!
masha68 [24]

Answer:

Power is the rate at which work is done

Explanation:

Power is the rate at which work is done. Power is measured in watts.

Work is the use of force to move an object. Work is measured in joules.

5 0
3 years ago
Read 2 more answers
A projectile is shot vertically upward with a given initial velocity. It reaches a maximum height of 72.0 m. On a second shot, t
exis [7]

Answer:

Explanation:

Given

maximum height reached h=72\ m

suppose Projectile is launched vertically with initial velocity u

applying equation of motion

v^2-u^2=2 as

where v=final velocity

u=initial velocity

a=acceleration

s=displacement

Here final velocity is zero so

s=frac{u^2}{2g}

for twice initial velocity

s'=\frac{(2u)^2}{2g}

s'=4\times \frac{u^2}{2g}

s'=4\times 72

s'=288\ m

5 0
3 years ago
A driver pushes on a car with a force of 8000 N for 15 seconds but is unable to move it. How much work is done
quester [9]

Answer:

the work done is zero.

Explanation:

Given;

applied force, F = 8000 N

time of force application, t = 15 s

Work done is given as the product of force and displacement. Since the car is unable to move, then the displacement is zero and the work done is zero.

Work done = Force x displacement

Work done = 8000 N x 0

Work done = 0

Therefore, the work done is zero.

5 0
3 years ago
Calculate the centripetal force exerted on the earth by the sun. Assume that the period of revolution for the earth is 365.25 da
Doss [256]

Answer:

F = 3.55 x 10²² N

Explanation:

average distance of sun from earth = 1.5 × 10⁸ km

mass of earth = 6 x 10²⁴ kg

time = 365.25 days

distance = 2 π r

distance = 2 π x 1.5 x 10¹¹ m

              = 3 π x 10¹¹ m

v = \dfrac{d}{t}

v = \dfrac{3 \pi \times 10^{11}}{365.25 \times 24 \times 60 \times 60}

   v = 2.98 x 10⁴ m/s

we know centripetal force

F = \dfrac{mv^2}{r}

F = \dfrac{6 \times 10^{24}\times (2.98\times 10^4)^2}{1.5\times 10^{11}}

F = 3.55 x 10²² N

8 0
3 years ago
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