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Fantom [35]
4 years ago
3

Nitrogen gas and hydrogen gas react to form ammonia according to the following thermochemical equation. 3H2+N2⟶2NH3ΔH=−96kJ Writ

e the balanced chemical equation for a reaction involving these substances with the following change in enthalpy. ΔH=192kJ Enter a balanced chemical equation. Do NOT enter phase designations.
Chemistry
2 answers:
Soloha48 [4]4 years ago
8 0

Answer:

6H2+2N2⟶4NH3ΔH=−192kJ

Explanation:

192/96=2 so we will obtain twice the energy then we need twice the equivalents and twice the coefficients.

Musya8 [376]4 years ago
7 0

Answer:

4 NH₃ ⟶ 6 H₂ + 2 N₂     ΔH= 192 kJ

Explanation:

Let's consider the following thermochemical equation.

3 H₂ + N₂ ⟶ 2 NH₃     ΔH= −96 kJ

According to Lavoisier-Laplace law, if we reverse this reaction, its enthalpy will have the same value and opposite sign than that of the direct reaction.

2 NH₃ ⟶ 3 H₂ + N₂     ΔH= 96 kJ

Enthalpy is an extensive property, that is, it depends on the amount of matter. If we double the amount of matter (by multiplying the stoichiometric coefficients by 2), the enthalpy will also be doubled.

4 NH₃ ⟶ 6 H₂ + 2 N₂     ΔH= 192 kJ

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LekaFEV [45]

The correct option is (C) 6.02 X 10²³

A sample of CH₄O with a mass of 32.0 g contains <u>6.02 X 10²³</u> molecules of CH₄O.

To calculate the number of moles;

Molar mass of CH₄O = C + 4(H) + O

          = 12.01 + 4(1.008) + 16

          = 32.04 g/mol

So, 1 mol of CH₄O = 32.04 g of CH₄O

Given, 32.0 g of CH₄O

According to Avagadro's constant 1 mole of a substance contains 6.022× 10^23 particles (molecules, atoms or ions).

 = (32.0 g/1)(1 mol CH₄O/32.04 g CH₄O)(6.02x10²³/1 mol CH₄O)

 = 6.02 X 10²³ molecules of CH₄O

Hence, a sample of  will contain  number of molecules 6.02 X 10²³ molecules.

Learn more about the Moles calculation with the help of the given link:

brainly.com/question/21085277

#SPJ4

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2 years ago
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satela [25.4K]
Mg + 2HCl = H₂ + MgCl₂

n(HCl)=c(HCl)v(HCl)

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Answer:

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Explanation:

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