PbI(ii) ionization in the solution of PBI(ii) into water is:
<span>PbI</span>₂(solution) <==> Pb₂⁺ + 2I⁻
If the conc. of PbI(ii) in the sol. is xM then the conc. of Lead(ii) will be x M and conc. of iodide will be 2 x M.
Therefore,
<span>Ksp=<span>[Pb</span></span>²⁺][I-]²
Plugging the values:
1.4×10⁻⁸ = x ⋅ (2x)²
1.4×10⁻⁸ = 4x³
x³ = {1.4×10⁻⁸}÷4
x³ = 0.35 x 10⁻⁸
or
x³ = 3.5 x 10⁻⁹
x = 1.51 x 10⁻³
Hence,
Concentration of iodide ions in the solution:
2x = 3.02 x 10⁻³
Answer:
The red blood cell is made to transport oxygen around the body.
Explanation:
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Answer:
E. Gain of electrons
Explanation:
A reduction reaction is one part of the two concurrent reactions that take place in a redox (reduction-oxidation) reaction.
During reduction, an atom gains electrons from a donor atom, and it's oxidation number becomes smaller.
Option A is wrong because reduction does not increase oxidation state nor are neutrons involved
Option B is wrong because reduction is not a nuclear reaction (does not involve the nucleons)
Option C is wrong because reduction leads to reduction in oxidation state
Option D is wrong leads to a reduction in oxidation state when electrons are gained
Option E is correct because reduction involves gain of electrons
Answer:
Please find the structure of the hydrocarbon in the attachment section and details on how to draw it in the explanation section.
Explanation:
Heptane is a member of the alkane group, which has a general formula of CnH2n+2. If n in heptane is 7, this means that the chemical formula for heptane will be C7H16 i.e.
= C7H2(7) + 2
= C7H14+2
= C7H16
C7H16 is the chemical formula for heptane, which is a linear hydrocarbon with 7 carbon atoms and 16 hydrogen atoms. However, in the name of the hydrocarbon compound given in the question: 2,3-dimethylheptane;
- Two methyl groups (CH3) has a substituted two hydrogen atoms specifically at carbon 2 and 3 respectively. Therefore, the new chemical formula of 2,3-dimethylheptane will be: C7H14(CH3)2
Please find the structural formula of the compound; 2,3-dimethylheptane as an attachment.
Answer:
Error percentage = 1.326% , 1.35% , 5.37%
density = mass / volume
For first sample:
density = 37.22/11.5 = 3.2365 g/ml
then percentage error = 100% - (3.2365/3.28 ) * 100 = 1.326%
For second sample:
density = 37.21/11.5 = 3.2356 g/ml
then percentage error = 100% - ( 3.2356 / 3.28 ) *100 = 1.35%
For third sample:
density = 37.25/12 = 3.104 g/ml
then percentage error = 100% - ( 3.104 / 3.28 ) *100 = 5.37%