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Norma-Jean [14]
3 years ago
15

Which of the following actions in a car cause it to accelerate? Select all that apply.

Physics
2 answers:
Oksi-84 [34.3K]3 years ago
7 0

Answer:

Option (b) will be correct answer for accelerating the car

Explanation:

For accelerating the car we have to speed up the car

In option (b) it is given that stepping on the gas pedal to speed up the car so it is correct answer

In option (c) it is given that pressing the pedal to slow down the car it is a case of deceleration so it is a incorrect statement.

In option (d) it is given that speed is constant at curved path so acceleration will be zero because if there is no change in velocity then acceleration will be zero  

mote1985 [20]3 years ago
3 0

Answer:

option (a)

Explanation:

The acceleration is defined as the rate of change of velocity. It is a vector quantity and its SI unit is m/s^2.

Acceleration = rate of change of velocity

a = \frac{v-u}{t}

As the car is accelerating, it means we are pushing the accelerating paddle.

So, the stepping on the gas pedal to speed the car up.

Thus, option (a) is correct.

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Which description best explains the distortion of color at the bottom of the leaves in the image?
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4 years ago
Calculate the specific heat at constant volume of water vapor, assuming the nonlinear triatomic molecule has three translational
vampirchik [111]

Answer:

I) c=1385.667\frac{J}{kg K}

II)The difference from the value obtained on part I is: 2000-1385.67 =614.33 \frac{J}{Kg K}

The possible reason of this difference is that the vibrational motion can increase the value, since if we take in count this factor we will have a higher heat capacity, because molecules with vibrational motion require more heat to vibrate and necessary higher specific heat capacity.

Explanation:

From the problem we have the molar mass given M=18\frac{gr}{mol} of water vapor and at constant volume condition. It's important to say that the vapour molecules have 3 transitionsl and 3 rotational degrees of freedom and the rotational motion no contribution.

Part I

Calculate the specific heat at constant volume of water vapor, assuming the nonlinear triatomic molecule has three translational and three rotational degrees of freedom and that vibrational motion does not contribute. The molar mass of water is 18.0 g/mol=0.018kg/mol.

Let C_v (\frac{J}{Kg K}) the molar heat capacity at constant volume and this amount represent the quantity of heat absorbed by mole.

Let C (\frac{J}{Kg K}) the specific heat capcity this value represent the heat capacity aboserbed by mass.

For the problem we have a total of 6 degrees of freedom and from the thoery we know that for each degree of freedom the molar heat capacity at constant volume is given by C_v =\frac{R}{2} so the total for the 6 degrees of freedom would be:

C_v =6*\frac{R}{2}=3R=3x8.314\frac{J}{mol K}=24.942\frac{J}{mol K}

And by definition we know that the specific heat capacity is defined:

c=\frac{C_V}{M}

If we replace all the values we have:

c=\frac{24.942\frac{J}{mol K}}{0.018\frac{kg}{mol}}=1385.667\frac{J}{kg K}

So on this case the specific heat capacity with constant volume and with three translational and three rotational degrees of freedom is c=1385.667\frac{J}{kg K}

Part II

The actual specific heat of water vapor at low pressures is about 2000 J/(kg * K). Compare this with your calculation.

The difference from the value obtained on part I is: 2000-1385.67 =614.33 \frac{J}{Kg K}

The possible reason of this difference is that the vibrational motion can increase the value, since if we take in count this factor we will have a higher heat capacity, because molecules with vibrational motion require more heat to vibrate and necessary higher specific heat capacity.

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