Elevation would be showing you what height you are at, energy would be like what force your putting into the object.
Given: Heat Qout means useful work = 2800 J
Heat Qin = 8900 J
Required; Efficiency = ?
Formula: Efficiency = Qout/Qin = x 100%
= 2800 J/8900 J = 0.3146 X 100 %
Efficiency = 31.46%
Is an enhancement of the bump mapping<span> or normal </span>mapping<span> techniques applied to textures in 3D rendering applications such as video games.</span>
In
order to determine the mass of a standard baseball if it had the same density
(mass per unit volume) as a proton or neutron, we first determine the volume of
the baseball. The formula to be used is V_sphere = (4/3)*pi*r^3. In this case, the
radius r can be obtained from the circumference C, C = 2*pi*r. After plugging
in C = 23 cm to the equation, we get r = 3.6066 cm. The volume of the baseball
is then equal to 205.4625 cm^3.
Next,
take note of these necessary information:
Mass of a neutron/proton
= 10^-27 kg
Diameter of a
neutron/proton = 10^-15 m
Radius of a
neutron/proton = [(10^-15)/2]*100 = 5x10^-14 cm
<span>Thus,
the density, M/V of the neutron/proton is equal to 1.9099x10^12 kg/cm^3. Finally,
the mass of the baseball if it was a neutron/proton can be determined by
multiplying the density of the neutron/proton with the volume of the baseball. The
final answer is then a large value of 3.9241x10^14 kg.</span>
Initial kinetic energy = 0J (v=0 (rest))
Final kinetic energy = 1/2mv ²
Ek=1/2(9)(27 ²)
Ek=4.5(729)
Ek=3280.5
∆Energy=3280.5J
(As it starts from 0)
Work= ∆energy
So work =3280.5J
Answer=3300J (forth option)