Answer:
A) = 0.63 m
B)This is approximately 0.21
Explanation:
Part A)
Now if spring is connected to the block then again we can use energy conservation
so we will have
so we will have
so total distance moved upwards is
Part B
Now the incline has a coefficient of kinetic friction μk. If the block, attached to the spring, is observed to stop just as it reaches the spring's equilibrium position, what is the coefficient of friction μk
KE = 8.75 – 10.78 * sin 41
This is approximately 1.678 J. This is the kinetic energy at the equilibrium position. For the block to stop moving at this position, this must be equal to the work that is done by the friction force.
Ff = μ * 10.78 * cos 41
Work = 0.5 * μ * 10.71 * cos 41
μ * 10.78 * cos 41 = 8.75 – 10.78 * sin 41
μ = (10 – 8.82 * sin 41) ÷ 8.82 * cos 41
μ = 1.678/8.136
μ = 0.206
This is approximately 0.21
Answer:
The distance of the runners from the flag pole is 1.28 miles west of the flagpole
Explanation:
Both the runners will meet at the same time = t
Distance they will cover together = 7 + 1 = 8 miles
Let speed of runner A = v₁ = 5 mph
Let speed of runner B = v₂ = 2 mph
Distance = Speed × Time
v₁t+v₂t = 8
Distance covered by runner A = v₁t = 5× (8/7) = 5.71 miles
Distance of runner A from flagpole = 7-5.71 = 1.28
The distance of the runners from the flag pole is 1.28 miles west of the flagpole.
By how many neutrons are in the atom
skin cancer and it cause to lost transportating process
Answer: Newton's first law of motion states that an object at rest remains at rest and an object in motion remains in motion with the same velocity unless acted upon by what we call an unbalanced force. There for the answer is A