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vitfil [10]
3 years ago
5

One would use deductive reasoning to

Physics
1 answer:
Ivan3 years ago
5 0
The answer is Prove a hypothesis
You might be interested in
A teacher pushed a 98 newton desk across a floor for a distance of 5 meters. He exerted a horizontal force of 20 N for four seco
Pie

Answer:

First let's find the work.

Work = Force*Displacement

= 20*5

= 100 Joules

Power = Work/Time

= 100/4

= 25 Watts

7 0
3 years ago
You are accelerating upwards in an elevator when the net force on you increases. What happens to the acceleration
Diano4ka-milaya [45]

Answer:

the acceleration of the elevator is increasing

Explanation:

For this exercise we propose the solution using Newton's second law

         F -W = m a

         F = m (g + a)

If the net force increases, it implies that the acceleration of the elevator is increasing, since the acceleration of gravity is constant as the ascent is accelerating.

7 0
3 years ago
The magnitude of a vector can be positive or negative The magnitude of a vector can be less than the magnitude of one of its com
NARA [144]

Answer:

If magnitude of vector A is less than magnitude of vector B then its x-component will be also less      

Explanation:

In first case magnitude can never be negative -ve sign shows the direction only so it is incorrect statement.

The magnitude of any vector can never be less than its component because component of vector is found with the multiplication of sine and cos angle which values lies between 0 and 1 so after multiplication it gives less value than the vector

If magnitude of any vector is less then its x component will also be less because magnitude of component is dependent on the magnitude of vector

8 0
3 years ago
10 A particle in circular motion performs 30 oscillations in 6<br> seconds. Its angular velocity is?
Snezhnost [94]

Explanation:

Let omega = angular velocity (in rad/s). Then

omega = (# of oscillations)/(6 s)

= (30 osc)/(6 s) = 5 osc/s

We need to convert this to rad/s:

omega = (5 osc/s)(2π rad/osc)

= 10π rad/s

= 31.4 rad/s

7 0
3 years ago
A mass spectrometer is being used to separate common oxygen-16 from the much rarer oxygen-18, taken from a sample of old glacial
Mashcka [7]

Answer: 0.076 m

Explanation:

Magnetic force= centripetal force;

F(B) = F(c) --------------------------(1)

Bqv= mv^2/R---------------------(2)

Where B= magnetic field,q= charge, = mass, R= radius of the circular path.

Radius of the circular path,R= mv/qB.

Mass of oxygen-16 is 2.66e−26kg, and they are singly charged = 18/16(mass ratio= 18:16)

18/16 × (2.26 × 10^ -26 kg)

= 2.99 × 10^26 kg

∆d=2r(18)-2r(16)-----------------(3)

r(18) is the radius of mass of oxygen-18,

r(16) is the radius of mass of oxygen-16.

From the question, v= 3.7×10^6 m/s, q= 1.6×10^-9 C.

From equation (2) above we have;

R= MV/qB------------------------(4)

This equation (4) is used in solving for the distance between the two.

Solving;∆d=2r(18)-2r(16)

∆d = 2[m(18) - m(16)] v/ qB

M(18)-m(16) =(2.99-2.66)× 10^-26:

qB= 1.6×10^-19×2 = 3.2×10^-19

= (2.99-2.66)× 10^-26/ 3.2× 10^-19

= 0.076 m

7 0
3 years ago
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