Answer:
P₂ = 130.18 kPa
Explanation:
In this case, we need to apply the Gay-Lussack's law assuming that the volume of the container remains constant. If that's the case, then:
P₁/T₁ = P₂/T₂ (1)
From here, we can solve for the Pressure at 273 K:
P₂ = P₁ * T₂ / T₁ (2)
Now, all we need to do is replace the given data and solve for P₂:
P₂ = 340 * 273 / 713
<h2>
P₂ = 130.18 kPa</h2>
Hope this helps
Of the three sources listed, geothermal energy
is the least dependent on the weather.
(Once it's installed and running, that is.)
Answer: Thus the solubility of 
gas in water, at the same temperature, if the partial pressure of gas is 10.0 atm is 235mg/100g.
Explanation:-
The Solubility of 
in water can be calculated by Henry’s Law. Henry’s law gives the relation between gas pressure and the concentration of dissolved gas.
Formula of Henry’s law, 
.
= Henry’s law constant = ?
The partial pressure (P) of in water = 4.07 atm
\
At pressure of 10.0 atm
Thus the solubility of gas in water, at the same temperature, is 235mg/100g
D. breakdown of rocks through mechanicals or chemicals processes
CxHy + O2 --> x CO2 + y/2 H2O
Find the moles of CO2 : 18.9g / 44 g/mol = .430 mol CO2 = .430 mol of C in compound
Find the moles of H2O: 5.79g / 18 g/mol = .322 mol H2O = .166 mol of H in compound
Find the mass of C and H in the compound:
.430mol x 12 = 5.16 g C
.166mol x 1g = .166g H
When you add these up they indicate a mass of 5.33 g for the compound, not 5.80g as you stated in the problem.
Therefore it is likely that either the mass of the CO2 or the mass of H20 produced is incorrect (most likely a typo).
In any event, to find the formula, you would take the moles of C and H and convert to a whole number ratio (this is usually done by dividing both of them by the smaller value).
