Question

A tennis ball is shot vertically upward from the surface of an atmosphere-free planet with an initial speed of 20.0 m/s. One second later, the ball has an instantaneous velocity in the upward direction of 15.0 m/s. A) How long does it take the ball to reach its maximum height?B) How high does the ball rise?C) What is the magnitude of the acceleration due to gravity on the surface of this planet?D) Determine the velocity of the ball when it returns to its original position. Note: assume the upward direction is positive.E) How long has the ball been in the air when it returns to its original position?

Answer 1

Answer:

(A) t = 4s

(B) H = 40m

(C) g = 5m/s²

(D) V = -20m/s

(E) t = 8s

The detailed solution to this problem requires the knowledge of costant linear acceleration motion.xplanation:

The detailed solution to this problem requires the knowledge of costant linear acceleration motion.

Explanation:

The full solution can be found in the attachment below.

To answer part A, we have been given some values of velocities bounding the time jnterval of 1s from which we can calculate the acceleration due to gravity and then the time.

Part B

Requires just using the acceleration due to gravity and the time taken in the equation

H = ut - 1/2gt²

Part C

Has already been calculated in part A

Part D

V = -20m/s because the tennis ball is coming down as the upward direction was assumed positive.

Part E

When the ball retirns to its original position it is the same as it never left and so H = 0m

The calculation can be found in the attachment below.