Answer:
Power = 15[W]
Explanation:
This problem can be solved using the work definition.
Work is equal to the product of the force by the distance, for this problem we have:
F = force = 30 [N]
d = distance = 30 [m]
w = work = F * d = 30*30 = 900 [J], "units in joules"
The power is defined as the work done in an interval of time.
P = w / t
where:
t = time [s]
therefore
P = w / t
P = 900 / 6
P = 150 [W] "units in watts"
First of all, let's write the equation of motions on both horizontal (x) and vertical (y) axis. It's a uniform motion on the x-axis, with constant speed

, and an accelerated motion on the y-axis, with initial speed

and acceleration

:


where the negative sign in front of g means the acceleration points towards negative direction of y-axis (downward).
To find the distance from the landing point, we should find first the time at which the projectile hits the ground. This can be found by requiring

Therefore:

which has two solutions:

is the time of the beginning of the motion,

is the time at which the projectile hits the ground.
Now, we can find the distance covered on the horizontal axis during this time, and this is the distance from launching to landing point:
When sounds at two different frequencies are combined,
two new sounds are created ... at the sum and difference
of the original frequencies.
Combining two sounds at 490 Hz and 488 Hz creates
beats at 978 Hz and 2 Hz.
The fluttering "wah wah" effect of the 2 Hz beat is much more
noticeable than the new sound at 978 Hz.
Answer: There is only one Sun in the galaxy … that is the thing that rises in the morning and sets at night. However, there is a use of “sun” to signify any old star … nobody knows exactly there might be trillions out there
Explanation:
Answer:
about 4.74 seconds
Explanation:
The time to fall distance d from height h is given by ...
t = √(2d/g)
t = √(2·110 m/(9.8 m/s^2)) ≈ 4.74 s
It will take the car about 4.74 seconds to fall 110 meters to the river.
__
We assume the car's speed is horizontal, so does not add or subtract anything to/from the time to fall from the height.