2 years ago

Your physics teachers want to race each other using wagon rockets.

1 answer:

5 0

Answer:

s=1/2at^2

s=1/2 x 4 x(10)^2=200m

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Oksana_A [137]

Answer:

$m=1.01\times 10^6\ kg$

Explanation:

Given that,

Pressure, P = 1 atm = 101325 Pa

Area of the square surface, A = 10² = 100 m²

We need to find the mass of vertical column of air. We know that, pressure is equal to the force acting per unit area. So,

$P=\dfrac{mg}{A}\\\\m=\dfrac{PA}{g}\\\\m=\dfrac{101325\times 10^2}{10}\\\\m=1.01\times 10^6\ kg$

So, the required mass of the vertical column of air is $1.01\times 10^6\ kg$ .

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2 years ago

Dima020 [189]

True !! Hope I helped you out a bit!

7 0

3 years ago

forsale [732]

Better weight distribution and more stability

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2 years ago

Romashka-Z-Leto [24]

Answer:

Push with force of 1N

Explanation:

I have explained in the paper.

Goodluck

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2 years ago

Black_prince [1.1K]

Ais the correct answer

4 0

2 years ago