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Alecsey [184]
3 years ago
15

Your physics teachers want to race each other using wagon rockets.

Physics
1 answer:
Genrish500 [490]3 years ago
5 0

Answer:

s=1/2at^2

s=1/2 x 4 x(10)^2=200m

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The amount of erosion created by a river is affected by all of the following except
SashulF [63]

Answer:

This answer to this one should be <em><u>Volume</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>Water</u></em><em><u>.</u></em>

5 0
3 years ago
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Which change would result in a stronger electromagnet?
Sonbull [250]
I'd say B.) Increasing the voltage of the battery.
6 0
3 years ago
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Which of the following is a measure of disorder or randomness
garri49 [273]

<u>Answer</u>:

D. Entropy is a measure of disorder or randomness

<u>Explanation</u>:

The answer is entropy. It is the method to measure any disorder or randomness of any system. Basically it is concept of physics and chemistry but can also be used in other subject matters as well. In formula terms, it is denoted by S and is measurement value is "Joule per kelvin". The values could be both positive and negative as well.

All the other options are incorrect as heat, energy and temperature are the different concepts of science which do not relates with any measurement.

5 0
3 years ago
A box weights 50kg applies friction force of 125N. You apply a force of 150N going in the right direction. What is the total net
Pachacha [2.7K]

Answer:

Net force  = 25N  and in the right direction

Explanation:

mass of box, m = 50kg

Force of block = 150N

Friction force = 125N

Net force  = Force Applied - Friction force =  F - F_f

150 - 125 = 25N

the force applied to the block is greater than the friction force. there the force applied will overcome the friction force and move in the right direction of the force applied

4 0
4 years ago
A positive charge of 18nC is evenly distributed along a straight rod of length 4.0 m that is bent into a circular arc with a rad
sergey [27]

Explanation:

Formula for angle subtended at the center of the circular arc is as follows.

           \theta = \frac{S}{r}

where,   S = length of the rod

              r = radius

Putting the given values into the above formula as follows.      

                \theta = \frac{S}{r}

                             = \frac{4}{2}

                             = 2 radians (\frac{180^{o}}{\pi})

                             = 114.64^{o}

Now, we will calculate the charge density as follows.

                 \lambda = \frac{Q}{L}

                            = \frac{18 \times 10^{-9} C}{4 m}

                            = 4.5 \times 10^{-9} C/m

Now, at the center of arc we will calculate the electric field as follows.

                 E = \frac{2k \lambda Sin (\frac{\theta}{2})}{r}

                     = \frac{2(9 \times 10^{9} Nm^{2}/C^{2})(4.5 \times 10^{-9}) Sin (\frac{114.64^{o}}{2})}{2 m}

                      = 34.08 N/C

Thus, we can conclude that the magnitude of the electric eld at the center of curvature of the arc is 34.08 N/C.

5 0
3 years ago
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