Answer:
V₂ = 14.07 L
Explanation:
As this gas is cooled at constant temperature of 320 K, this means that we are on an isothermal process, and according to the 1st law of thermodynamics:
Q = W (1)
And as the temperature is constant, we can use the following expression to calculate the Work done:
W = nRT ln(V₁/V₂) (2)
However, as Q = W, we can replace heat into the above expression and then solve for V₂:
Q = nRT ln(V₁/V₂)
Replacing we have:
1200 = (1.5 * 8.314 * 320) ln(19/V₂)
1200 = 39907.2 ln(19/V₂)
ln(19/V₂) = 1200/3990.72
ln(19/V₂) = 0.3007
19/V₂ = e^(0.3007)
V₂ = 19 / e^(0.3007)
<h2>
V₂ = 14.07 L</h2>
Hope this helps
Answer:
C. Sources of electrical current!
Hope this helps :)
Answer:
The time he can wait to pull the cord is 41.3 s
Explanation:
The equation for the height of the skydiver at a time "t" is as follows:
y = y0 + v0 · t + 1/2 · g · t²
Where:
y = height at time "t".
y0 = initial height.
v0 = initial velocity.
t = time.
g = acceleration due to gravity (-9.8 m/s² considering the upward direction as positive).
First, let´s calculate how much time will it take for the skydiver to hit the ground if he doesn´t activate the parachute.
When he reaches the ground, the height will be 0 (placing the origin of the frame of reference on the ground). Then:
y = y0 + v0 · t + 1/2 · g · t²
0 m = 15000 m + 0 m/s · t - 1/2 · 9.8 m/s² · t²
0 m = 15000 m - 4.9 m/s² · t²
-15000 m / -4.9 m/s² = t²
t = 55.3 s
Then, if it takes 4.0 s for the parachute to be fully deployed and the parachute has to be fully deployed 10.0 s before reaching the ground, the skydiver has to pull the cord 14.0 s before reaching the ground. Then, the time he can wait before pulling the cord is (55.3 s - 14.0 s) 41.3 s.
Explanation:
Given that, the height of the tide measured at a seaside community varies according to the number of hours t after midnight. The height is given by the equation as :
When the tide first be at 6 ft, put h = 6 ft in above equation as :
On solving the above equation to find the value of t. It is equal to :
t = 3.551 seconds
or
t = 8.449 seconds
So, the tide of 6 ft is at 3.551 seconds and 8.449 seconds. Hence, this is the required solution.
Answer: they could get a piece of the coral and run tests on it
Explanation:
