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Hoochie [10]
2 years ago
14

The percent ionization of benzoic acid, 2.05 %, at a particular concentration is 25 °C. What was the concentration of benzoic ac

id in this solution? Ka of benzoic acid is 6.3 × 10-5
Chemistry
1 answer:
Mkey [24]2 years ago
3 0

Answer : The concentration of benzoic acid in this solution was, 0.149 M

Explanation :

The balanced equilibrium reaction will be,

                          C_6H_5COOH\rightleftharpoons C_6H_5COO^-+H^+

initially conc.             c                     0                0

At eqm.                    c(1-α)                cα              cα

The expression for dissociation constant is:

k_a=\frac{c\alpha\times c\alpha}{c(1-\alpha)}

when α is very very small the, the expression will be,

k_a=\frac{c^2\alpha^2}{c}=c\alpha^2

Given:

α = 2.05 % = 0.0205

K_a=6.3\times 10^{-5}

Now put all the given values in this expression, we get:

6.3\times 10^{-5}=c\times (0.0205)^2

c = 0.149 M

Therefore, the concentration of benzoic acid in this solution was, 0.149 M

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8 0
3 years ago
What are the chemicals used to preserve food and give it color and flavor​
Lelechka [254]

Answer:

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Explanation:

6 0
2 years ago
What is the specific heat of a substance if 6527 J are required to raise the temperature of a 312 g sample by 15 degrees Celsius
Tanzania [10]

Answer:

1.395J/g°C

Explanation:

The following were obtained from the question:

Q = 6527J

M = 312g

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C =?

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C = 6527/(312 x 15)

C = 1.395J/g°C

The specific heat capacity of the substance is 1.395J/g°C

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3 years ago
A gas cylinder contains exactly 15 moles of oxygen gas (O2) how many molecules of oxygen are in a cylinder
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How many grams of sodium sulfide can be produced when 45.3 g Na react with 105 g S?
RoseWind [281]
The chemical reaction would be as follows:

<span>2Na + S → Na2S

We are given the amount of the reactants to be used in the reaction. We use these to calculate the amount of product. We do as follows:

45.3 g Na ( 1 mol / 22.99 g ) = 1.97 mol Na
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8 0
2 years ago
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