Answer:
The time required by the impulse to travel from foot to brain equals 0.019 seconds
Explanation:
For uniform motion the distance, speed, time are related by the equation
![Distance=Speed\times time](https://tex.z-dn.net/?f=Distance%3DSpeed%5Ctimes%20time)
In our case since the person is 1.90 meters tall so the nerve impulse will have to cover a distance of 1.90 meters at a speed of 100 m/s.
Hence the time required for the impulse to travel from foot to the brain can be calculated as
![time=\frac{Distance}{speed}\\\\\therefore time=\frac{1.90m}{100m/s}=0.019seconds](https://tex.z-dn.net/?f=time%3D%5Cfrac%7BDistance%7D%7Bspeed%7D%5C%5C%5C%5C%5Ctherefore%20time%3D%5Cfrac%7B1.90m%7D%7B100m%2Fs%7D%3D0.019seconds)
Using a process of testing ideas and gathering evidence.
Answer:
Explanation:
Component of force perpendicular to stick
= F Sin 60°
=√3 / 2 F.
Taking torque about the other end
= √3 / 2 F x 1 Nm
Weight of stick = 60 gm
= 60 x 10⁻³ kg
= 60 x 10⁻³ x 9.8 N
= .588 N
This weight will act from the middle point of stick so torque about the
other end
= .588 x 1 Nm
Balancing these two torques we have
.588 = √3 /2 F
![F=\frac{2\times0.588}{\sqrt{3} }](https://tex.z-dn.net/?f=F%3D%5Cfrac%7B2%5Ctimes0.588%7D%7B%5Csqrt%7B3%7D%20%7D)
F = 0.679 N
Given that 1 ounce equals 28.35 grams, the value of 14.600 ounces in grams is approximately 413.9g.
<h3>What is the value of 14.600 oz in grams?</h3>
Note that:
1 ounce = 28.35 grams
Given that;
- Value of mass = 14.600 oz
- Value of mass in grams
Since 1 ounce = 28.35 grams, 14.600 oz will be;
14.600 oz = ( 14.600 × 28.35) grams
14.600 oz = 413.9g
Given that 1 ounce equals 28.35 grams, the value of 14.600 ounces in grams is approximately 413.9g.
Learn more about conversion of ounces to gram here: brainly.com/question/1117493
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