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marissa [1.9K]
3 years ago
8

I'll give brainliest can someone help me with 2.4.1-2.4.3?with explanation. ​

Physics
1 answer:
KIM [24]3 years ago
8 0

Answer:

220÷4=550 per hour

2.4.3 550×4=2200

hope it's right

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3 years ago
Part D- Isolating a Variable with a Coefficient In some cases, neither of the two equations in the system will contain a variabl
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Answer:

D)     D = \frac{5}{4}  - \frac{3}{4} \ C, E)  (C, D) = ( \frac{17}{7}, \ \frac{-4}{7}

Explanation:

Part D) two expressions are indicated

          3C + 4D = 5

          2C +5 D = 2

let's simplify each expression

         3C + 4D = 5

         4D = 5 - 3C

we divide by 4

            D = \frac{5}{4}  - \frac{3}{4} \ C

The other expression

       2C +5 D = 2

       2C = 2 - 5D

        C = 1 -  \frac{5}{2} \ D

we can see that the correct result is 1

Part E.

It is asked to solve the problem by the substitution method, we already have

          D =  \frac{5}{4}  - \frac{3}{4} \ C

we substitute in the other equation

            2C +5 D = 2

             2C +5 (5/4 - ¾ C) = 2

we solve

            C (2 - 15/4) + 25/4 = 2

             -7 / 4 C = 2 - 25/4

             -7 / 4 C = -17/4

              7C = 17

               C = \frac{17}{7}

now we calculate D

               D = \frac{5}{4} - \frac{3}{4} \ \frac{17}{7}

               D = 5/4 - 51/28

               D =\frac{35-51}{28}

               D = - 16/28

               D = - \frac{4}{7}

the result is (C, D) = ( \frac{17}{7}, \ \frac{-4}{7} )

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