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Ede4ka [16]
4 years ago
14

a 95 kg football player is initially running at 8.25 m/s. The football player slows down to .47 m/s. What is the change in kinet

ic energy
Physics
1 answer:
aliya0001 [1]4 years ago
8 0
Change in KE = K_initial - K_final
= (½)m(v_final)² - (½)m(v_initial)²
= (½)(95)(0.47)² - (½)(95)(8.25)²
= -3222.476
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A rubber-wheeled 50 kg cart rolls down a 35 degree concrete incline. Coefficient of rolling friction between rubber and concrete
lapo4ka [179]

Answer:

(a) 5.62 m/s²

(b) 5.46 m/s²

Explanation:

The given values are:

mass,

m = 50 kg

angle

= 35°

(a)

If friction neglected,

⇒ F_x=mgSin \theta=ma

⇒ a_x=gSin \theta

       =9.8 \ Sin35^{\circ}

       =5.62 \ m/s^2

(b)

If friction present,

⇒ F_x=mgCos \theta

⇒ F_x=mgSin \theta-\mu_r mgCos \theta

⇒ a=gSin \theta-\mu_rgCos \theta

      =9.8 \ Sin35^{\circ}-0.02\times 9.8 \ Cos30^{\circ}

      =5.46 \ m/s^2

8 0
3 years ago
What must be the distance between point charge 91 = 20 MC and point charge 02 -45,0 AC for the electrostatic force between them
Fynjy0 [20]

Answer:

Explanation:

Q₁ = 20 X 10⁻⁶ C

Q₂ = -45 X 10⁻⁶ C

d is required distance.

F = Force between the = 7 N

F = k x Q₁ X Q₂ / d²

d² = k x Q₁ X Q₂ / F = 20 X 45 X 10⁻¹² X 9 X 10⁹  /7

=1.157

d = 1.075 m

7 0
4 years ago
A trumpeter is placed on a moving sidewalk that moves at a constant velocity of 4.5 m/s. A listener is standing 6.0 m in front o
swat32
You didn't actually include the speed of sound. But it doesn't matter for this question. If the trumpeter and the listener are on the same moving sidewalk then the distance between them is not changing. The Doppler shift only happens when the distance between the source and the Observer is changing. So the Listener hears the same 290 Hertz that the trumpeter is generating.
7 0
4 years ago
A softball player moving 3.89 m/s
guapka [62]

Answer:

0.119 s is the correct answer to this question.

Explanation:

As mentioned in the question

U=3.89\ m/s

a=-1.44\ m/s^2

S=4.8\ m

Consider the final speed of the softball covering the distance of 4.8m is v

Now using the equation

v^2=U^2+2aS

Putting the value of U, A, S in the previous equation we get

V^2=3.89^2-2\times 1.44\times 4.8\\V=3.7\ m/s\\

Now again using the equation

v=U+at

where U=intial velocity, t= time

Substituting the value of v, U, a

3.7=3.89-1.44\times t\\t=0.119\ s\\

Hence the slide time is 0.119 s

7 0
3 years ago
Explanation of the physics involved i the northern lights(aurora borealis) why can't it occur in mire southerns latitudes?
PSYCHO15rus [73]

Answer:

The northern lights come from the interaction of electrically charged particles given off by the Sun surface during solar storms and the Earth's magnetic field which is pointed in the northern to southern poles of the Earth. Therefore, the charged particles that travel through millions of miles from the Sun to the Earth accelerate towards the magnetic poles and appear as the northern (and southern) lights

Boreal is an adjective word for the north or northern regions. In the southern latitudes, in the southern hemisphere, the phenomenon is called aurora australis (australis is the adjective for 'of the south')

Explanation:

5 0
3 years ago
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