Draw a square that is meant to represent you, draw an up arrow, a down arrow, a right arrow, and a left arrow. The Left arrow is FORCE FRICTION which is the floor adding friction against you, the Right arrow is FORCE APPLIED, which is the force that your legs are using to cause you to move, the Up arrow is FORCE NORMAL, which is the force that always act on something that is affected by gravity, and the Down arrow is FORCE GRAVITY. These are the four forces acting on you as you walk to the kitchen
Answer:
12N
Explanation:
We are given that one of the forces are acting only in the horizontal x-direction. As a force must be applied on an object of mass in order to cause acceleration, the 6.0ms^-2 acceleration is due to the non-horizontal force acting on the 2.0kg object.
Using Newton's Second Law of motion; we know that for a constant mass, force is equal to mass times acceleration, F=ma.
Assuming the other force is acting only in the vertical direction (question doesn't specify, thus we are finding the minimum force to cause this acceleration):
F= 2.0kg * 6.0ms^-2
F=12.0 kgms^-2
F=12 N
The answer is 86 degrees Fahrenheit. Formula is (30 x 9.5) + 32 = 86
(a) The ball’s maximum speed over the net is v(max) = √2gh.
(b) The maximum speed of the horizontally moving ball clearing the net is about 27 m/s.
(c) Speed of the ball is independent of its mass.
<h3>
Time of motion of the ball</h3>
The time of motion of the ball is calculated as follows;
h = vt + ¹/₂gt²
1 = 0 + ¹/₂(9.8)t²
1 = 4.9t²
t² = 1/4.9
t² = 0.204
t = 0.452 s
<h3>Horizontal speed of the ball</h3>
The horizontal speed of the ball is calculated as follows;
X = vt
v = X/t
v = (12 m)/(0.452)
v = 26.6 m/s ≈ 27 m/s (proved)
<h3>Conservation of energy</h3>
P.E = K.E
mgh = ¹/₂mv²
gh = ¹/₂v²
2gh = v²
√2gh = v(max)
Speed of the ball is independent of its mass.
Learn more about horizontal velocity here: brainly.com/question/24681896
#SPJ1
The electric potential energy of the pair of charges when the second charge is at point b is U at b = +7.3×10⁻⁸J.
Electric potential is the amount of work done in moving point charge from infinity to aspecific point.
Calculation of the electric potential energy:
Here the particle should be moved from the point at the time when the potential energy should be U a
The U b should be the change in the potential energy
W is work done.
(W at a )-(W at b) = U a - U b
U b = U a - (W at a )+(W at b)
So,
= 5.4 × 10⁻⁸J - ( -1.9×10⁻⁸ J)
= +7.3×10⁻⁸J.
Learn more about electric potential here:
brainly.com/question/24284560
#SPJ4